The numbers 272738 and 232342 when divided by n a 2 digit number leave a remainder of 13 and 17

ans is 7
subtracting 272738 with remainder will make a divisible number.
so 272738-13=272725
dividing 272725 with 5,we get 54545,and again diving by 5 we get 10909
so the divided number is 5*5=25
hence the sum of the nuber is 7
10 years agoHelpfull: Yes(14) No(1)
13 and 17 comes from the last two digits of given numbers
272738-xxxx25=13 , 232342-xxxx25=17
10 years agoHelpfull: Yes(9) No(3)
option: a
272738/n=13->272738-13=272725 it is divide by 25
232342/n=17->232342-17=232325/25
so sum of digit is 7
10 years agoHelpfull: Yes(3) No(0)
as remainder is 13 & 17 so dividend must be greater than 17

272738 = n*a+13 => 272725=n*a ---(1)
232342 = n*b+17 => 232325=n*b ---(2)

last two digit of (1)&(2) is 25 so n must be 25, no other two digit no. greater than 25 satisfies this

n=25, sum of digits of n = 2+5 = 7
8 years agoHelpfull: Yes(1) No(0)
ans- 25
2+5=7
10 years agoHelpfull: Yes(0) No(8)
121-130 5's =1
131-140 =1
141-150 =2
151-160 =10
161-170 =1
171-180 =1
so,121-200 = 18
201-300 = 21
301-356 = 12
total = 51
10 years agoHelpfull: Yes(0) No(6)
rakesh pls provide correct sol for this
10 years agoHelpfull: Yes(0) No(2)
ans is a.
10 years agoHelpfull: Yes(0) No(0)

The numbers 272738 and 232342, when divided by n, a 2 digit number, leave a remainder of 13 and 17 respectively. Find the sum of the digits of n?
a. 7
b. 8
c. 5
d. 4