TCS
Company
Numerical Ability
Time and Work
A can do a particular work in 6 days . B can do the same work in 8 days. A and B signed to
do it for Rs. 3200. They completed the work in 3 days with the help of C. How much is to be
paid to C?
A. Rs. 380
B. Rs.
600
C. Rs. 420
D. Rs.
400
Read Solution (Total 5)
-
- Amount of work A can do in 1 day = 1/6
Amount of work B can do in 1 day = 1/8
Amount of work A + B can do in 1 day = 1/6 + 1/8 = 7/24
Amount of work A + B + C can do = 1/3
Amount of work C can do in 1 day = 1/3 - 7/24 = 1/24
work A can do in 1 day: work B can do in 1 day: work C can do in 1 day
= 1/6 : 1/8 : 1/24 =4:3:1
Amount to be paid to C = 3200 * (1/8) = 400 - 10 years agoHelpfull: Yes(36) No(4)
- A's one day wage=3200/6
He worked for three days, his share=1600
B's one day wage=3200/8
His share for three days=1200
C's share=3200-(1600+1200)=1200
i.e for 3 days
C's one day share=400
- 10 years agoHelpfull: Yes(1) No(5)
- A&B=1/6+1/8=7/24 in 1 day
work done by a&b in 3 days=3*7/24=7/8
c'share=1/8*3200=400 - 10 years agoHelpfull: Yes(1) No(0)
- 1/a+1/b+1/c=1/3
1/c=1/3-(1/6+1/8)
1/c=1/24
it means c needs 24 days to complete the whole work
total amount=3200
and c works for 3 days
(3/24)*3200=400 - 7 years agoHelpfull: Yes(0) No(0)
- a=1/6 , b=1/8 , c=1/x.......
1/6+1/8+1/x=1/3...
x=24
than a:b:c=1/6:1/8:1/24
taking lcm,than we get..
4:3:1
for c=3200/8 = 400rs ....ans. - 7 years agoHelpfull: Yes(0) No(0)
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