How long does a train 110
meters long running at the speed of 72 km/hour take to cross a
bridge 132 meters in length ?
a)15 seconds
b)12.1 seconds
c)10 seconds
d)8.1 second

• Length of train is 110 m
  Length of Bridge is 132 m
  So, to pass train from the Bridge total distance travel is 242 m
  
  Speed of train is 72 km/hr.
  Therefore, in 1 sec train will travel 72*(5/18) = 20 m
  Now, to pass 242 m time required is 242/20 = 12.1 sec
  Option b is correct.
• 10 years agoHelpfull: Yes(38) No(0)
• b)12.1s
  132+110/20
• 10 years agoHelpfull: Yes(6) No(0)
• total lengt the train must travelled is 110+132=242
  speed is 72*(5/18)=20m/sec
  time=(242/20)=12.1sec
• 10 years agoHelpfull: Yes(6) No(0)
• St*T=(Lt+Lb)
  72*(5/18)T=110+132
  20T=242
  T=12,1seconds -----answer
  Lt=length of train
  Lb=length of bridge
  St=speed of train
  T=time
• 10 years agoHelpfull: Yes(1) No(0)
• dis=110+132=242
  time=242/20=8.1sec
• 10 years agoHelpfull: Yes(0) No(3)
• 72 km/hr in m/s = 72*5/18 = 20 m/s
  now total distance = 110+132 m = 242 m
  
  so,time = 242/20 = 12.1 seconds
• 10 years agoHelpfull: Yes(0) No(0)
• Length of train is 110 m
  Length of Bridge is 132 m
  So, to pass train from the Bridge total distance travel is 242 m
  
  Speed of train is 72 km/hr.
  Therefore, in 1 sec train will travel 72*(5/18) = 20 m
  Now, to pass 242 m time required is 242/20 = 12.1 sec
  Option b is correct.
• 10 years agoHelpfull: Yes(0) No(2)
• TRAIN CROSSING A STATIONARY OBJECT WITH THE LENGTH
  THEN THE FORMULA: (speed of the train)*time=(length of the train+length of the object)
  here speed of the train: 72km/h=72000m/h length of the train: 110 meter
  length of the bridge: 132 meter
  so, 72000*t=110+132
  => t=242/72000 => t= 0.00336 h= 0.00336*3600 sec =12.1 sec (b)
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• ans should be (b)
• 10 years agoHelpfull: Yes(0) No(0)
• speed 72km/hr
  convert it into m/sec=72*(5/18)=20 m/sec.
  Total distance covered=110+132=242 meter.
  
  time=distance/speed.
  time=242/20
  time=12.1seconds.
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• 12.1 seconds
• 9 years agoHelpfull: Yes(0) No(0)