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Maths Puzzle
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Find min value of fn: |-5-x| + |2-x|+|6-x|+10-x|; where x is an integer
Read Solution (Total 7)
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- 19
| -5 - x | + | 2 - x | + | 6 - x | + | 10 - x |
which can be written as
| 5 + x | + | x - 2 | + | 6 - x | + | 10 - x | >=
| (5 + x) + (x - 2) + (6 - x) + (10 - x)| = 19. - 13 years agoHelpfull: Yes(16) No(6)
The answer is 19. | -5 - x | + | 2 - x | + | 6 - x | + | 10 - x | = | 5 + x | + | x - 2 | + | 6 - x | + | 10 - x | >= | (5 + x) + (x - 2) + (6 - x) + (10 - x)| = 19. This means the minimum can not be 0 or 17, so it is either 19 or 23. Since equality holds when x = 2, 19 is in fact the minimum.- 13 years agoHelpfull: Yes(5) No(4)
- @MRINAL ACTUALLY IT WILL GIVE 19 AS VALUE BY PUTTING X=2,3,4....... U CAN TRY IT SO ANSWER IS 19
- 13 years agoHelpfull: Yes(3) No(2)
- Can anyone explain this | 5 + x | + | x - 2 | + | 6 - x | + | 10 - x | >=
why sign of first two || are changed and not of whole statement?
- 10 years agoHelpfull: Yes(3) No(1)
- if x=0
then 5+2+6+10=23
min value of fn=23 - 13 years agoHelpfull: Yes(1) No(9)
- Each term has a minimum value of zero because of the absolute values.
So the minimum for the function is zero.
So the answer is Zero. - 9 years agoHelpfull: Yes(1) No(2)
- y sign ll not change in |6-x| & |10-x| ?
- 11 years agoHelpfull: Yes(0) No(1)
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