Self
Maths Puzzle
Numerical Ability
find the number of numbers that can be formed using all the digits 1,2,3,4,3,2,1 only once so that the odd digitts occupy old place only?/
Read Solution (Total 3)
-
- 6 no only can be made
- 10 years agoHelpfull: Yes(1) No(0)
- 12
here 1,1,3,3 is odd .so ie,4*3*2*1/2*1=12.1 is repeated 2 times & 3 is repeated 2 times .in given Q,i digit should take only once. - 10 years agoHelpfull: Yes(0) No(0)
- (4!/(2!*2!))(3!/2!)=18
- 10 years agoHelpfull: Yes(0) No(0)
Self Other Question