A train can cross a bridge of length 650 m in 10 seconds and a bridge of length 450m in 8 seconds . find the average speed of the train.

• 360km/hr.
  x=length f train
  (650+x)/10=(450+x)/8
  =>x=350 mt
  (350+650)/10=100mt/sec=360km/hr
  
• 10 years agoHelpfull: Yes(32) No(8)
• let train length is = x
  so (650 +x)/10 is speed of first train ----(1)
  
  and (450 + x)/8 is speed of second train-----(2)
  
  solving 1 and 2
  we get x= 350
  now putting the value of x in both 1 and 2
  we get speed 100m/s
  in both equaton
  so ans is 100m/s
  
  
  
  
  
• 10 years agoHelpfull: Yes(7) No(4)
• avg speed is total distance upon total time
  650+450/18
• 10 years agoHelpfull: Yes(5) No(4)
• Speed= (650-450)/(10-8)
  =200/2
  =100 m/s
• 10 years agoHelpfull: Yes(5) No(1)
• Avg speed=total distance/total time
  So s=(650+450)/(10+8)=1100/18=61.11 m/s
• 10 years agoHelpfull: Yes(1) No(1)
• distance covered = 650+450
  = 1100
  time taken = 10
  avg speed = 1100/10 = 110 meter per second
• 10 years agoHelpfull: Yes(0) No(15)
• 62.5 metre per sec
  
• 9 years agoHelpfull: Yes(0) No(1)