How many numbers from 0 to 351 are not divisible by 2,3,5 & 7 .

• there is only one number inbetween 0 to 351 which is divisble by 2,3,5&7 is 210.
  there is only 352 numbers are present inbetween 0 to 351.
  so 351 are not divisible by 2,3,5 & 7;
  ans is 351
• 10 years agoHelpfull: Yes(26) No(11)
• from o to 100 number of number divisible by 2=50
  similarly frm 100 to 200 =50
  from 200 to 300 =50
  from 300 to 351 we have 25
  from 0 t0 100 number of numbers divisble by 3 but not 2 is 17
  similarly frm 100 to 200 =17
  frm 200 to 300 =17
  frm 300 to 351=8
  from 0 to 100 the number of nubers divisible by 5 bt not 2 and 3 is 7
  similarly frm 100 to 200 =7
  frm 200 to 300 =7
  frm 300 to 351 we have only 1
  frm 0 to 100 the no of numbers divisible by 7 bt not 2,3,5 are =4
  similarly from 100 to 200= 4
  frm 200 to 300 =4
  frm 300 to 350 we have 0
  hence totally....frm 0 to 351 the number of numbers not divisible by 2,3,5,7 are
  352-(50+50+50+25+17+17+17+8+7+7+7+1+4+4+4+0)
  352-(274)
  ans=78
  
  
• 10 years agoHelpfull: Yes(19) No(1)
• LCM of 2,3,5 and 7 is 210.
  The next number divisible by all 4 numbers will be a multiple of 210.
  The nearest multiple of 210 will be 210*2=420 which is greater than 351.
  So, only 2 numbers are divisible i.e. 0 and 210.
• 10 years agoHelpfull: Yes(11) No(3)
• i think guys u are taking it wrong it was actually asking for the number which are not individually not divisible by 2,3,5,7, like 11,13,17,19,23, etc and their multiples .. am i ri8??
• 10 years agoHelpfull: Yes(6) No(0)
• 0.........because lcm of 2,3,5&7 is 210 so no number are divisible between 0to 351
  
• 10 years agoHelpfull: Yes(2) No(13)
• divisibility by 2 for no.s b/w 0 to 351-
  no b/w 0 to 300=150 and no b/w 300 to 351=25
  total=175
  
  divisibility by 3 but not 2 for no.s b/w 0 to 351-
  series of such no.s = 3,9, 15,.........., 351
  by A>P. total no of terms => 351=3+(n-1)6
  so, n =59
  
  divisibility by 5 but not 2&3 for no.s b/w 0 to 351-
  
  no.s divisible by 5 but not 2&3 between 0 to 100 = 7
  similarly count between 100 to 300 = 14 more such terms
  now no.s between 300 to 351 divisible by 5 but not 2&3 = 305,325,335=3
  total no of terms = 7+14+3=24
  
  divisibility by 7 but not 2,3&7 for no.s b/w 0 to 351-
  from 0 to 100 (7,49,77,91)=4
  similarly from 100 to 200 (119,133,161,182)=4
  similarly from 200 to 300 (203,217,259,287)=4
  from 300 to 351 (301,329,343)=3
  
  total no of terms = 4+4+4+3=15
  
  so numbers divisible b/w 0 to 351 not divisible by 2,3,5&7 = 352-(175+59+24+15)
  = 79 answer
  
  
  
• 10 years agoHelpfull: Yes(2) No(0)
• All prime numbers between 0-351 are not divisible by 2,3,5,7.
  
• 10 years agoHelpfull: Yes(1) No(1)
• Ans. 2
  0 and 210
• 10 years agoHelpfull: Yes(0) No(4)
• total number is 88
  nos divisible by 2 = 180
  nos divisible by 3 (not by 2)= 59
  nos divisible by 5(not by 2 3) = 12
  nos divisible by 7 ( not by 2,3,5) = 13
  
  summing up we get 264 which are divisible
  so nos not divisible is 352-264 = 88
  
  as the total numbers are 352
  
  
• 9 years agoHelpfull: Yes(0) No(0)