A can complete a piece of work in 8 hours, B can complete in 10 hours and C in 12 hours. If A,B, C start the work together but A laves after 2 hours. Find the time taken by B and C to complete the remaining work.

1) 2 (1⁄11) hours
2) 4 (1⁄11) hours
3) 2 (6⁄11) hours
4) 2 hours

• A,B,C 1 hour work is=1/8+1/10+12= 37/120
  A,B,C work together for 2 hours, so,A,B,C 2 hours work is: (37/120)*2=37/60
  remaining work=1-37/60=23/60 (23/60 work is done by B and C together)
  B,C 1 hour work is= 1/10+1/12=11/60
  23/60 hours work done by B,C= (11/60)* (60/23)=11/23
  so... ans is: 2(1/11)
• 10 years agoHelpfull: Yes(57) No(6)
• total unit of the work is 120units
  In 1 hour A can complete 15units
  In 1 hour B can complete 12units
  In 1 hour C can complete 10units
  In 1 hour A+B+C can complete 37units
  Therefore in 2 hours A+B+C would have completed 74units
  Remaining work to be completed is 12-74=46
  In 1 hour B+C can complete 22units
  Therefore time taken to complete the remaining job =46/22=23/11=2(1/11)
  ans is 2(1/11)
• 10 years agoHelpfull: Yes(37) No(1)
• 1)2(1/11)hours
  
  The time taken by A+B+C to do the work is (1/8+1/10+1/12)=37/120
  work done by ABC in 2 hours = (37/120) x 2 = 37/60
  there work left = 1-(37/60) = 23/60
  
  B+C can complete the work in = ( 1/10+1/12 )= 11/60
  
  therefore time taken by BC = 11/60 x 60/23 = 23/11 = 2(1/11) hours
  
• 10 years agoHelpfull: Yes(4) No(0)
• a=1/8
  b=1/10
  c=1/12
  a+b+c=1/8+1/10+1/12
  =(15+12+10)/120
  =37/120 [in 1 hr]
  In 2 hr,work done=37/60
  work left=1-37/60
  =23/60
  b+c=1/10+1/12
  =(6+5)/60
  =11/60
  time taken by b and c=23/60 x 60/11
  =23/11
  =2(1/11) hr
  
• 10 years agoHelpfull: Yes(4) No(2)
• A leaves after 2 hours=2/8
  B=x/10
  C=x/12
  Total work=1
  2/8+x/10+x/12=1
  After solving we get x=45/11
  Ans=4(1/11)hrs
• 9 years agoHelpfull: Yes(2) No(6)
• One day work of A : 1/8
  One day work of B : 1/10
  One day work of c : 1/12
  A,B,C work together for 2 days : 37/120*2
  37/60
  Remaining work : 1-37/60
  23/60
  B and C work together to do the remaining work :60/11*23/60
  23/11
  2(1/11)hours
  
• 8 years agoHelpfull: Yes(2) No(0)
• A,B,C 1 hour work = 1/8+1/10+1/12=37/120
  A leaves after 2 hour so total time required to complete the work is:
  2/8+X/10+X/12=1
  15+6X+5X=60
  X = 4(1/11)
  
  but question is Find the time taken by B and C to complete the remaining work so we subtract the A's 2 hours work .
  so X=4(1/11)-2
  X=2(1/11) Hours.
• 5 years agoHelpfull: Yes(2) No(0)
• Ans : 2(1/11)
• 10 years agoHelpfull: Yes(1) No(4)
• Option A
  1hr work of all three=37/120
  2hr work=37/60,
  work left=23/60,
  efficiency of b & c =11/60
  work left = (23/60)/(11/60)
  Ans=2(1/11)
• 10 years agoHelpfull: Yes(1) No(0)
• 2/8 +x/10 +x/12 =1
  
  so x=4(1/11)
• 9 years agoHelpfull: Yes(1) No(1)
• total unit of the work is 120units
  In 1 hour A can complete 15units
  In 1 hour B can complete 12units
  In 1 hour C can complete 10units
  In 1 hour A+B+C can complete 37units
  Therefore in 2 hours A+B+C would have completed 74units
  Remaining work to be completed
  (ie) (total work-work done) is120-74=46
  In 1 hour B+C can complete 22units
  Therefore time taken to complete the remaining job =46/22=23/11=2(1/11)
  ans is 2(1/11)
• 8 years agoHelpfull: Yes(1) No(0)
• 2*(1/8)+x/10+x/12=1
  22x/120=3/4
  x=45/11
  4(1/11)
• 8 years agoHelpfull: Yes(1) No(0)
• Ans=4(1/11)hour
  A=8hours,B=10hours,C=12hours
  Total work A,B,C=LCM OF A,B,C=120work
  A=120/8=15work/hour
  B=120/10=12work/hour
  C=120/12=10work/hour
  
  Let total work =Xhour
  A left in 2 hours
  15(2)+12x+10x=120
  X=4(1/11)hour
• 7 years agoHelpfull: Yes(1) No(0)
• 1/8+1/10+1/12 = 37/60
  
  1-37/60=x(1/10+1/12)
  
  solve for x
• 10 years agoHelpfull: Yes(0) No(2)
• aswer is 1
• 10 years agoHelpfull: Yes(0) No(6)
• answer is 2)
• 9 years agoHelpfull: Yes(0) No(0)
• A,B,C WORK in 2 hr is =2(1/8+1/10+1/12)
  
• 9 years agoHelpfull: Yes(0) No(0)
• A,B,C work in 2 hr is = 2(1/8+1/10+1/12)= 37/60
  remaining work is 1-37/60=23/60
  let x be total no days to complete a work by B,C
  x(1/10+1/12)=23/60
  x=23/11 --------------------------- x=2(1/11)
  
• 9 years agoHelpfull: Yes(0) No(0)
• 2(1/11)hrs
• 8 years agoHelpfull: Yes(0) No(1)
• work done by A+B+C in 2 hours is 37/60
  so remaining work is 1-37/60=23/60
  work done by B+C in 1 hour is 11/60
  so the remaining work done by B+C is 2(1/11) hours.
• 7 years agoHelpfull: Yes(0) No(1)
• A-->8hrs
  B-->10hrs
  C-->12hrs
  
  assume total work done to be=120units(l.c.m of all 3 time)
  
  rate of work of A= 120/8=15units/hr
  rate of work of B= 120/10=12units/hr
  rate of work of C= 120/12=10units/hr
  total rate of A,B and c=15+12+10=37units/hr
  i.e,
  In 1 hour=37units is done by a,b,c
  So, in 2 hours=74units of work is done by a,b,c
  
  120-74=46units is the reaming work left to be done by B and C
  
  in 1 hr B and C takes 32units of work(12units/hr+10units/hr)
  So, in 2(1/11)hrs ,46 units of work is done
  
  ANS=2(1/11)
• 5 years agoHelpfull: Yes(0) No(0)
• Answer is (1) 2 (1/11)
• 5 years agoHelpfull: Yes(0) No(0)