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If x+y=25 and x^2y^3 + y^2x^3=25, what is the value of xy?
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- x2y2(x+y)=25
(xy)^2=1
xy=+1,-1 - 10 years agoHelpfull: Yes(22) No(4)
x^2*y^3 + y^2*x^3=25
=> x^2*y^2*(y+x)=25
=> x^2*y^2*25=25 [given, x+y=25]
=> (xy)^2 = 1
=> xy = 1- 10 years agoHelpfull: Yes(21) No(1)
- x2y3+x3y2=25
x2y2(x+y)=25
x2y2=1
xy=1 - 10 years agoHelpfull: Yes(8) No(1)
- answer is 1
x2y2(x + y ) = 25
hemce xy = 1 - 10 years agoHelpfull: Yes(2) No(0)
- x2y3+x3y2=25
x2y2(x+y)=25
x2y2=1
xy=1 - 10 years agoHelpfull: Yes(1) No(0)
- x2y2(x+y)= 25
(xy)^2= 1
so, xy= +1 or -1 - 10 years agoHelpfull: Yes(1) No(1)
- 1 is the ans
- 10 years agoHelpfull: Yes(0) No(0)
- since x+y= x^6y +y^6x thus 6x=6y=1
x=y=1/6
thus xy =1/36 - 10 years agoHelpfull: Yes(0) No(4)
- 1 is answer
- 10 years agoHelpfull: Yes(0) No(0)
- from second eq. x^2*y^2 is taking common
so x^2*y^2(y+x)=25
(xy)^2=25/25
xY=1,-1 - 10 years agoHelpfull: Yes(0) No(0)
- (x^2)(y^3)+(y^2)(x^3)=25
(x^2)(y^2)(x+y)=25
(x^2)(y^2)=1
xy=1 - 10 years agoHelpfull: Yes(0) No(0)
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