The temperature during first day of a week is 37 degree Celsius and that of during last day is 32 degree Celsius. If the temperature of these two days are excluded, the average temperature of the remaining days is 2 degree Celsius lesser than the average temperature of the week. What is the average temperature of the week (in degree Celsius)?

29.5
degree celsius
10 years agoHelpfull: Yes(8) No(2)
If x is average temp of week, then
7x-5(x-2)= 37+32=69
2x+10=69
2x=59
x=29.5 deg celsius
10 years agoHelpfull: Yes(5) No(0)
29.5degree celsius
10 years agoHelpfull: Yes(1) No(1)
ans=29.5
let average temp of week be x.
then average temp of remaining days =x-2.
now [37+32+5(x-2)]/7=x which gives 29.5.
10 years agoHelpfull: Yes(1) No(0)
23.07 degree celsius
10 years agoHelpfull: Yes(0) No(4)
i got 39.5........
10 years agoHelpfull: Yes(0) No(7)
ans =45.5
x1=37,x2,x3,x4,x5,x6,x7=32
x2+x3+x4+x5+x6/5-2=37+x2+x3+x4+x5+x6+32/7
hence x2+x3+x4+x5+x6=415/6
total average=415/6+37+32/3
45.5
10 years agoHelpfull: Yes(0) No(6)
(x2+x3+x4+x5+x6)/5=((37+x2+x3+x4+x5+x6+32)/7)-2
(x2+x3+x4+x5+x6+10)/5=(69+x2+x3+x4+x5+x6)/7(by cross multiply)
7x2+7x3+7x4+7x5+7x6+70=345+5x2+5x3+5x4+5x5+5x6
2(x2+x3+x4+x5+x6)=275
x2+x3+x4+x5+x6=137.5
(69+x2+x3+x4+x5+x6)/7=(69+137.5)/7=29.5
10 years agoHelpfull: Yes(0) No(2)
let temp of the remaining 5 days be A
ATQ
a/5= 32+a+37 /7 -2
a=137
thus the avg temp =69+a/7=206.5= 29.5
10 years agoHelpfull: Yes(0) No(0)
7x-(37+32)=5*(x-2)
this gives x=29.5 c
10 years agoHelpfull: Yes(0) No(0)
29.5 degree celcius.
10 years agoHelpfull: Yes(0) No(0)
let x be the avg of 7 days
so remaining 5 days avg be x-2
(37+5(x-2)+32)/7=x
x=29.5
10 years agoHelpfull: Yes(0) No(0)
(a+b+c+d+e)/5=(a+b+c+d+e+69)/7-2
;a+b+c+d+e=135
avg=135+69/7=29.14
10 years agoHelpfull: Yes(0) No(1)

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