One tank will fill in 6 minutes at the rate of 3cu ft /min, length of tank is 4 ft and the width is 1/2 of length, what is the depth of the tank?

• volume of tank=length*width*depth
  And volume given=3*6 cu ft.
  hence length*width*depth=3*6 cu ft
  4*(1/2*4)*depth=3*6 cu ft
  depth=(3*6)/ 4*(1/2*4) ft
  depth =2.25 ft
• 10 years agoHelpfull: Yes(32) No(6)
• mishra ji you are using the formula of are , not of volume which is l*b*h
  
  i think answer is 2.25 is correct
• 10 years agoHelpfull: Yes(4) No(3)
• vol=6x3=18 cu ft
  vol=len x wid x dep
  18=4 x 2 x dep
  dep=18/8
  =2.25 ft
  
• 10 years agoHelpfull: Yes(2) No(0)
• 9/4..i think
• 10 years agoHelpfull: Yes(1) No(0)
• volume of tank= rate of incoming substance*no. of time to incoming=length*width*height
  => 3*6=4*4/2*x
  =18/8
• 10 years agoHelpfull: Yes(1) No(0)
• 2.25ft.. is the depth
• 10 years agoHelpfull: Yes(0) No(0)
• total volume of the tank is 6*3=18cuft.
  for a cuboid volume is l*b+b*h+l*h solving depth will be 16/9
• 10 years agoHelpfull: Yes(0) No(6)
• 4*2*x=18cubic feet
  thus depth = 3 ft
• 10 years agoHelpfull: Yes(0) No(4)
• As we dont know the actuall shape of the tank..we can assume it to be a cylindrical tank..so in that case volume will be pi*r*r*h
  here r=1ft
  volume=6*3cu ft/min
  so pi*r*r*h=18
  h=18/pi viz=5.73.
• 9 years agoHelpfull: Yes(0) No(1)
• capacity of tank=6*3cc=18cc ft
  now length=4 ft...width=2 ft ...llet depth of tank is x ft
  so 18=legth*depth*width
  so 18=4*x*2
  so x=18/8=9/4=2.25ft
• 9 years agoHelpfull: Yes(0) No(0)
• Total time taken to fill in the tank=6mins
  Volume covered in 1min=3 cu ft
  So volume covered in 6mins=6*3=18 cu ft
  Lenth of tank=4ft
  Width of tank= 1/2of length=1/2*4=2ft
  Height of tank be x
  Vol of tank =length*width*height
  18=x*4*2
  X=9/4=2.25ft
  Height of tank is 2.25ft
• 9 years agoHelpfull: Yes(0) No(0)