3 persons A, B and C are standing in a queue. There are 5 persons between A and B and 8 persons between B and C. If there are 3 persons ahead of C and 21 persons behind A, what could be the minimum number of persons in the queue ?
Option
1) 41
2) 40
3) 28
4) 27

• positions : ---c--a-----b---------------
  totally 28
  ans is c
• 10 years agoHelpfull: Yes(66) No(9)
• arrangement is like this
  B
  5 person
  A
  3 person
  c
  17person
  plz include A,B,C while calculating answer
  so answer is 21+A+5+B which means 21+1+5+1=28
  option (3)
• 10 years agoHelpfull: Yes(30) No(8)
• Ans is 28.
  The sequence of persons are:
  3
  C
  2
  À
  5
  B
  15
• 10 years agoHelpfull: Yes(12) No(1)
• sorry, this is the right answer=28
  Justification:
  Three persons A, B, C can be arranged in a queue in six different ways i.e., ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements i.e., CBA and CAB. We may consider the two cases as under :
  3 8 5 21
  Case I : ← C ↔ B ↔ A →
  clearly, number of persons in the queue = (3 + 1 + 8 + 1 + 5 + 1 + 21) = 40.
  3 5
  Case II : ← C A ↔ B
  
  
  
  Number of persons between A and C = (8 - 6) = 2.
  Clearly, number of persons in the queue = (3 + 1 + 2 + 1 + 21) = 28.
  Now, 28 < 40. So, 28 is the minimum number of perosn in the queue.
• 10 years agoHelpfull: Yes(12) No(0)
• 40=5+8+3+21 and +3(itself A,B and C)
• 10 years agoHelpfull: Yes(9) No(10)
• The queue structure:
  (3persons)-C-(8persons)-B-(5persons)-A-(21persons)
  minimum is the addition of all the persons including C,B,A which is: 3+1+8+1+5+1+21=40
  ans is (2)-40
• 10 years agoHelpfull: Yes(5) No(0)
• 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,A,1,2,3,4,5,B,1,2,3,4,5,6,7,8,C,1,2,3====40 persons
• 10 years agoHelpfull: Yes(4) No(1)
• since Q is about minimum answer is 28
• 10 years agoHelpfull: Yes(3) No(1)
• ans= 2 i.e 40 persons
• 10 years agoHelpfull: Yes(2) No(2)
• since the order is not given we will arrrange it in such an order that it will give its min value so..
  if 21 +3(a b and c)+ 3=27 ans
• 10 years agoHelpfull: Yes(2) No(0)
• p1,p2......p21 A p1,p2...p5 B p1.....p8 C p1..p3
  21+A+5+B+8+C+3
  and A and B is also itself
  21+1+5+1+8+1+3=40
• 10 years agoHelpfull: Yes(2) No(2)
• 21...a-----b--------c---
  from the above fig. 21+a counts 1 place+5+1+8+1+3=40
  
• 10 years agoHelpfull: Yes(1) No(3)
• arrangement
  3
  c
  3
  a
  5
  b
  16
  
  =27
• 10 years agoHelpfull: Yes(1) No(3)
• Three persons A, B, C can be arranged in a queue in six different ways i.e., ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements i.e., CBA and CAB. We may consider the two cases as under :
  3 8 5 21
  Case I : ← C ↔ B ↔ A →
  clearly, number of persons in the queue = (3 + 1 + 8 + 1 + 5 + 1 + 21) = 40.
  3 5
  Case II : ← C A ↔ B
  
  
  
  Number of persons between A and C = (8 - 6) = 2.
  Clearly, number of persons in the queue = (3 + 1 + 2 + 1 + 21) = 28.
  Now, 28 < 40. So, 28 is the minimum number of perosn in the queue.
• 10 years agoHelpfull: Yes(1) No(0)
• according to question..
  21 a 5 b 8 c 3
  so..21+5+8+3+3(a b and c)=40 as total
• 10 years agoHelpfull: Yes(0) No(1)
• 40 as the sum would be 21 + 1+5+1+8+1+3= 40
• 10 years agoHelpfull: Yes(0) No(1)
• 21+1+5+1+8+1+3=40
  ans is 40
• 10 years agoHelpfull: Yes(0) No(3)
• - - - c- - a- - - - -b- - - - - - - - - - - - - - -
• 10 years agoHelpfull: Yes(0) No(0)
• 40
  3 ahead of c+8 between B and c+5 between a and b+21 behind a + A,B,C themselves
  so altogether 40
• 10 years agoHelpfull: Yes(0) No(0)
• Three persons A, B, C can be arranged in a queue in six different ways, ie ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements, ie CBA and CAB.
  We may consider the two cases as under:
  Case I:
  Clearly, number of persons in the queue = (3+1+8+1+5+1+21=) 40
  Case II:
  Number of persons between A and C
  = (8 - 6) = 2
  Clearly number of persons in the queue = (3+1+2+1+21) = 28
  
  Now, 28 < 40.
  
  So, 28 is the minimum number of persons in the queue.
  
• 10 years agoHelpfull: Yes(0) No(0)
• cant understand the spacing between c and a as 2
• 9 years agoHelpfull: Yes(0) No(0)
• arrangement
  3
  c
  3
  a
  5
  b
  16
  
  =27
  
• 9 years agoHelpfull: Yes(0) No(1)