TCS
Company
Numerical Ability
Number System
146!/5^n what is the maximum value of n?
Option
A) 34
B) 35
C) 36
D) 37
Read Solution (Total 6)
-
- exponent of 5 in 146! = [146/5]+[146/5^2]+[146/5^3]= 29+5+1 = 35
i.e. 146! has a factor 5^35
146!/5^n => n(max)=35 - 10 years agoHelpfull: Yes(38) No(0)
- ANS B 146/5=29 146/25=5 146/125=1 SO 29+5+1=35
- 10 years agoHelpfull: Yes(2) No(0)
- 146/5 = 29
146/5^2= 5
146/5^3 = 1 therefore ans is 29+5+1= 35 (B) - 10 years agoHelpfull: Yes(2) No(2)
- 146/5+146/25+146/125
- 10 years agoHelpfull: Yes(1) No(2)
- we will choose a number such that 5^x 5^4=625 so we will exclude x=4. we will choose x=3.
now for x=1 to 3 we will do
(Summation of)(146/5^x)
146/5^1 + 146/5^2 +146/5^3=29+5+1=35. - 10 years agoHelpfull: Yes(1) No(0)
- the ans is 35
146/5=29
29/5=5
5/5=1
29+5+1=35 - 10 years agoHelpfull: Yes(0) No(0)
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