IBM
Company
Numerical Ability
Number System
How many 5's are there in the number 121122123...till 356
Read Solution (Total 8)
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- 121122123... till 356
121,122,123,124... till 356
121 to 200 => 125,135,145, from 150 to 159 => 11 5's , 165,175,185,195
[from 150 to 159, each no. has 1 no. of 5 except 155, 155 has 2 no. of 5]
total=18
201 to 300 => 205,215,225,235,245, 250 to 259 => 11 5's , 265,275,285,295
=> total=20
301 to 356 => 305,315,325,335,345,350,351,352,353,354,355(2 5's),356
=> total=13
total no. of 5's = 18 + 20 + 13 = 51
- 10 years agoHelpfull: Yes(42) No(0)
- the no. includes 5 from 121 to 200 are (125,135,145,150 to 159,165,175,185,195)
no. of 5's are = 18 (because 155 has two 5's)
from 201 to 300 (205,215,225,235,245,250 to 259,265,275,285,295)
no of 5's are =20
from 301 to 356 (305,315,325,335,345,350 to 356)
no. of 5's are 13
hence ans is 18+20+13=51 - 10 years agoHelpfull: Yes(2) No(0)
- its in the form of 121 122 123 124 and so on...
so simply calculate the number of 5's
125,135,145,150,155,165,175,185,195,205,215,225,235,245,250,255,265,275,285,295,305,315,325,335,345,350,355..
so altogeter there are 30 5's
- 10 years agoHelpfull: Yes(1) No(5)
- Answer is :51
- 10 years agoHelpfull: Yes(1) No(1)
- 48 times
given series is 121 122 123 124.....356
121 to 200 7+11=18(125,135,145,65,175,185,195)+(150,151,152,153,154,155,156,157,158,159)
201 to 300 9+11=20
301 to 356 5+8=13
total 5=51ans. - 10 years agoHelpfull: Yes(1) No(1)
- my ans is 30
- 10 years agoHelpfull: Yes(0) No(5)
- Yes its 51 only
- 10 years agoHelpfull: Yes(0) No(0)
- (8+1)+(10+1)+(5+1)=26
- 10 years agoHelpfull: Yes(0) No(2)
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