TCS
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Numerical Ability
Arithmetic
What is the sum of first 10000 numbers in the series -1,+1,-1,+1,-1.......??
Read Solution (Total 8)
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- i think sum is zero because the no of terms are even and alternative -1 and +1 will summed up as zero so zero would be correct ans
- 10 years agoHelpfull: Yes(19) No(0)
- Sum is 0
-1+1=0
and for 10000 numbers it will form 5000 pairs
so 5000*0 = 0 - 10 years agoHelpfull: Yes(5) No(0)
- it is gp......total terms n= 10000 r=-1 a=-1
sum=(a*((r^n)-1))/(r-1)
therefore sum=0 - 10 years agoHelpfull: Yes(2) No(0)
- zero since no of terms are even
- 10 years agoHelpfull: Yes(2) No(0)
- 0 as 5000 times +1-1 = 0
- 10 years agoHelpfull: Yes(0) No(0)
- As the powers of 3 may result in 3,9,7,1 as the units digit.And the series continues even the power raised to a larger number. so we divide the number by 4.
- 10 years agoHelpfull: Yes(0) No(0)
- 5000 pairs of (+1 & -1)=zero
- 10 years agoHelpfull: Yes(0) No(0)
- 0 I think sum is zero
- 10 years agoHelpfull: Yes(0) No(0)
TCS Other Question
On this island, there are three types of people. Knights, who always tell the truth, knaves, who always lie, and spies, who can do either. In these puzzles, you meet three people, one knight, one knave and one spy. The challenge is to determine who is who.
A says "I am a Knight"
B says "A is a Knight"
C says "If you asked me, I would say that A is the spy"
who is a??
what is average of 2000 terms of the given series
1,-3,2,-4,3,-5,4,....
A 1
B 0.5
C -0.5
D -1