When 76^77 is divided by 7,then what will be the remainder ??

• 6 will be the remainder
  
  (ax-1)^n/a will gives the remainder "1" for all even values of 'n' and "(a-1)" for all the odd values of 'n'
  
  here 76^77/7 ==> (7*11-1)^77/7 [a=7, x=11,n=77]
  
  here power "n" is odd
  
  so the remainder is (a-1) ie (7-1) which is "6"
  
  Ans : 6
• 10 years agoHelpfull: Yes(18) No(2)
• 
  @Ghanshyam Gulati
  ANS IS:6
  when u see problems like this(that is consecutive numbers(76 POWER 77))
  or
  FOR EXAMPLE
  ((32)^(33)^(34))/33
  WRITE THEM LIKE THIS: (32*33*34)/33
  THEN JUST DIVIDE INDIVIDUALLY =>(-1*1*+1)/33
  SO ANSWER WILL BE -1/33 I.E., 33-1=32(REMAINDER)
  COMING TO THE QUESTION (76^77)/7 JUST WRITE IT LIKE THIS (76*77)/7
  THEN (-1*1)/7=>-1/7=>7-1=6(REMAINDER)
• 10 years agoHelpfull: Yes(7) No(0)
• 42 because 6*7=42
  
• 10 years agoHelpfull: Yes(0) No(6)
• Units digit is 6
  On dividing 6 by 7 we get reminder -1
  So 7-1=6
  Reminder is 6
• 10 years agoHelpfull: Yes(0) No(0)
• Answer is 6-1777odd powerbecause as we can see on dividing 76 by 7 we get -1and power is odd thus it will remain -1 thus answer will be 7-16
• 10 years agoHelpfull: Yes(0) No(0)