76^77 /7
remainder is ?

• @Ghanshyam Gulati
  ANS IS:6
  when u see problems like this(that is consecutive numbers(76 POWER 77))
  or
  FOR EXAMPLE
  ((32)^(33)^(34))/33
  WRITE THEM LIKE THIS: (32*33*34)/33
  THEN JUST DIVIDE INDIVIDUALLY =>(-1*1*+1)/33
  SO ANSWER WILL BE -1/33 I.E., 33-1=32(REMAINDER)
  COMING TO THE QUESTION (76^77)/7 JUST WRITE IT LIKE THIS (76*77)/7
  THEN (-1*1)/7=>-1/7=>7-1=6(REMAINDER)
• 10 years agoHelpfull: Yes(23) No(1)
• as, 4^3/3=64/3 remainder=1 and also 4/3=1
  and 5^3/3 remainder=2 and also 5/3=2
  so it does not matter on the power value
  so the answer will be 76/7 remainder=6
• 10 years agoHelpfull: Yes(5) No(0)
• 6 will be the remainder
  
  (ax-1)^n/a will gives the remainder "1" for all even values of 'n' and "(a-1)" for all the odd values of 'n'
  
  here 76^77/7 ==> (7*11-1)^77/7 [a=7, x=11,n=77]
  
  here power "n" is odd
  
  so the remainder is (a-1) ie (7-1) which is "6"
  
  Ans : 6
• 10 years agoHelpfull: Yes(3) No(3)
• we can write the question as(70+6)^77/7
  thus everytime we'll get 6 as remainder,((6)^77/7)
  now,we can write it ((7-1)^77/7),
  thus now remainder would be((-1)^77/7)
  77 is odd thus (-1)/7=6
  ans:6
  
• 10 years agoHelpfull: Yes(2) No(0)
• (77-1)^77/7=(-1)^77
  =-1 but the remainder can not be negative
  so rem=-1+divisor=-1+7=6
  
• 10 years agoHelpfull: Yes(2) No(0)
• 76^77/7=(77 times 76)/7
  =76*76*76*76*....76(77times)/7
  now divide each 76 by 7
  =76/7 * 76/7 * 76/7 * ....76/7(77 times)
  now you will get 6 as reminder
  =6/7 * 6/7 * 6/7 *...6/7(77times)
  now ,multiply each term's nominator and divide by 7
  =36/7 * 36/7 * 36/7 *....36/7(38times) *6/7
  now you will get reminder as 1 for each term
  =1/7 * 1/7 *1/7....1/7(38times) * 6/7
  now multiply each nominator again
  =1(38 times)/7 * 6/7
  =1/7 * 6/7
  now again multiply nominator
  =6/7
  and you will get 6 as final reminder.
• 10 years agoHelpfull: Yes(1) No(0)
• (7*11-1)^77 / 7=(-1)77/7
  7-1=6
  so ans is 6
  
• 10 years agoHelpfull: Yes(1) No(0)
• 76%7=6
  whatever may be the power of 6. unit digit will be 6
  so remainder is 6
• 10 years agoHelpfull: Yes(1) No(0)
• 7*11-1/7
  (-1)^77/7=-1
  7-1=6
• 10 years agoHelpfull: Yes(1) No(0)
• 76^77/7
  (-1)^77/7
  -1/7
  REM -1 OR 6
• 10 years agoHelpfull: Yes(1) No(0)
• last 2 digits 0f 76^77 is 96.after dividing 96 by 7 remainder is 5
• 10 years agoHelpfull: Yes(0) No(7)
• 76^77/7=(77 times 76)/7
  =76*76*76*76*....76(77times)/7
  now divide each 76 by 7
  =76/7 * 76/7 * 76/7 * ....76/7(77 times)
  now you will get 6 as reminder
  
• 10 years agoHelpfull: Yes(0) No(0)
• ans is 6 as expression is of the form a^n/a+1
  76^77/7 = 6^77/7
• 10 years agoHelpfull: Yes(0) No(0)
• zero..as77/7=11 i,e zero remainder
• 10 years agoHelpfull: Yes(0) No(1)
• ans:6
  the given data 76^77/17 formula:a^n/(a+1) if n is odd=a if n is even=1 so the sum last unit digit 6^77 power is odd.the ans is 6.
• 10 years agoHelpfull: Yes(0) No(0)