Diamond\s value is proportional to its weight 2 .When the diamond broke what of pieces in ratio 1:2:3;4:5. Total loss in value is 85,000. What is the value of the diamond twice the wt of the original diamond.

• let weight of the original diamond be 15k ( This number is the sum of the numbers in the ratio given ) ,so, it's value would be 225k^2. Now, the broken diamond's value adds upto 55k^2. So, loss of value is 170k^2 which is 85,000. This gives k^2 = 500.
  
  We need (30k)^2 = 900k^2 = 900* 500 = 450,000
• 10 years agoHelpfull: Yes(22) No(3)
• from where this 55k^2 come??
• 10 years agoHelpfull: Yes(3) No(1)
• add the square of ratios u will get 55k^2...1+4+9+16+25=55
• 10 years agoHelpfull: Yes(3) No(0)