There are two pipes A and B.If A filled 10 liters in hour B can fills 20 liters in same time.likewise B can fill 10,20,40,80,160.... if B filled in (1/16)th of a tank in 3 hours.how much time will it take to fill completely?

• 1/16 in 3 hours
  1/8 in 4 hours,as here rate of water filling is doubled
  1/4 in 5 hours
  1/2 in 6 hours
  1 in 7 hours
  
  ans will be 7 hours
  
  
• 10 years agoHelpfull: Yes(36) No(3)
• 1/16 of a tank is filled in 3 hours.
  in 3 hr, tank is filled=40
  capacity of tank=40*16=640
  
  tank is filling in following manner
  10,20,40,80,160,320,640
  so, tank will filled in 7 hours.
  
• 10 years agoHelpfull: Yes(10) No(0)
• In 3hr --> 10+20+40=70lit. Total capacity=70*16=1120lit.
  remaining-->1120-70=1050lit.
  in the next 3hr-->80+160+320=560lit.
  remaining=1050-560=490lit.
  in the next hr it fill 640lit.
  To fill 490lit recquired time=(490/640)*60=46min.
  so total 3h+3h+46miin=6hr 46min the tank will full.
• 10 years agoHelpfull: Yes(4) No(0)
• 1/16 ----- 3hrs
  1 ------ X
  3/(1/16)=X
  X=48hrs
  
  
  or
  
  In 3 hours,
  B filled 20x3=60 litres
  
  60 litres=1/16 of tank
  
  capacity of tank= 60x16=960litres
  
  Time taken = 960 divided by 20 which is 48 hours
  
• 10 years agoHelpfull: Yes(3) No(4)
• Since in 3 hrs B filled 1/16 th of tank that is 40
  1/16 x =40
  x(total)=40*16= 640 litres
  time taken
  5 hr 160
  6 hr 320
  7 hr 640
  so 7 hrs
• 10 years agoHelpfull: Yes(3) No(0)
• 1/16 of the tank in 3 hrs
  10=1hr
  20=2hr
  40=3hr
  capacity in3 hrs is 40 litres
  40*16 total capacity=640 litres
  80=4hrs
  160=5hrs
  320=6hrs
  640=7hrs
  so the answer will be 7 hours
• 10 years agoHelpfull: Yes(2) No(0)
• in 3hrs it fills (1/16th) part
  so in 4th hr=2*(1/16)=1/8
  5th hr=2*(1/8)=1/4
  6th hr=2*(1/4)=1/2
  7th hr=2*(1/2)=1
  ans:7hrs
• 6 years agoHelpfull: Yes(0) No(0)