A student has 60% chance of passing in English and 54% chance of passing in both English and maths. What is the percentage probability that he will fail in maths ?

• Ans. Probability of failing in maths is 60%
  
  
  chance of passing in English= P(E)=60%
  chance of passing in both English and Maths = P(E n M)= 54%
  
  now let chances of passing in Maths be x
  
  therefore, chance of either passing in English or Maths = P(E U M)= 1 - P(E n M)
  = 1 - 54/100
  = 46/100
  = 46%
  
  now according to the formula=>
  
  P(AUB)=P(A)+P(B)-P(AnB)
  
  substituting values ==>
  
  46=60+x-54
  46=6+x
  40=x
  
  therefore chances of passing in maths are 40%
  hence by formula, P(A')=1 - P(A)
  we get,
  probability of failing in maths==>
  P(H')=1 - P(H)
  =1 - 40/100
  = 60/100
  =60%
  
  
• 10 years agoHelpfull: Yes(5) No(0)
• englishpass8mathpass=54/100
  60/100*x=54/100 => x=90/100.... x pass is 90%
  (1-x)=maths fail= 10%
• 10 years agoHelpfull: Yes(2) No(0)
• how to solve
  
• 10 years agoHelpfull: Yes(0) No(0)
• a=60/100,aub=54/100,
  AuB=A+B-AnB
  54/100=60/100+B-60/100B
  54/100-60/100=40/100B
  14=40B
  B=14/40=7/20
  
• 10 years agoHelpfull: Yes(0) No(3)
• suppose chance of paasing in english is P(E)=60%=60/100
  and chance of passing in math is P(M)=?
  
  P(EuM)=P(E) + P(M) - P(EnM)
  100/100=60/100+x-54/100
  1=6/100+x
  
  so chance of passing in math is 94/100
  
  so chance of fail in math is 1-94/100--------->6/100
• 10 years agoHelpfull: Yes(0) No(6)
• 14
  
  chance to fail in English=40
  
  Change of failing in both Maths and English =46
  
  So according to formula for probability=100-(40+46)
• 10 years agoHelpfull: Yes(0) No(0)