IBM
Company
Logical Reasoning
Number Series
What is the next number of the following sequence
9, 3, 6, 21, 9, 12, 33, 15, ...?
Read Solution (Total 15)
-
- 9-3=6
21-9=12
33-15=18 ANS - 10 years agoHelpfull: Yes(24) No(5)
- Look upon the series carefully
9,3, 6,21,9, 12,33,15
1st no - 2nd no. = 3rd no (it is the first multiple of 6)
9 - 3 = 6
4th no - 5th no = 6th no (it is the second multiple of 6)
21 - 9 = 12
similarly
7th no - 8th no = 9th no.(it will be 3rd multiple of 6)
33 - 15 = __
so answer will be 18 - 10 years agoHelpfull: Yes(14) No(2)
- 6+3=9
9+12=21
then
15+18=33
so ans is 18 - 10 years agoHelpfull: Yes(3) No(1)
- 9,3,6,21,9,12,33,15,x
9=3+6
21=9+12
33=15+x
=> x=18 - 10 years agoHelpfull: Yes(1) No(1)
- (9,3,6),(21,9.12),(33,15,?)
3*1=3
3*2=6
(3+6)=9
Similarly,3*3=9
3*4=12
(9+12)=21
So, 3*5=15
3*6=18
(15+18)=33
So ans is 18 - 10 years agoHelpfull: Yes(1) No(0)
- 9,3,6,21,9,12,33,15
here we are using method to get a solution is
substract 2nd number from 1st number inorder to get 3rd number i.e: 9-3=6
simailarly 21-6=9
finally 33-15=18
ANS:18 CORRECT - 10 years agoHelpfull: Yes(0) No(2)
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- 10 years agoHelpfull: Yes(0) No(2)
- 9-3=6
21-9=12
33-15=18 - 10 years agoHelpfull: Yes(0) No(2)
- answer 18
3+6=9
9+12=21
18+15=33 - 10 years agoHelpfull: Yes(0) No(2)
- 18 is the next no. of the given sequence...coz
taking 3 no at once first_no = second_no. + third_no.
e.g. 9 = 3 +6
21= 9+ 12
33= 15+ 18 - 10 years agoHelpfull: Yes(0) No(2)
- 18
dividing the numbers by 3 we get the series as
3,2,1,7,3,4,33,15...
we can see that 3-2=1,7-3=4,11-5=6
so multiply 6*3=18 - 9 years agoHelpfull: Yes(0) No(1)
- ans=18
exp.
9-6=3
21-12=9
33-x=15
x=18 - 9 years agoHelpfull: Yes(0) No(1)
- 6+3=9
9+12=21
15+x=33
x=7. - 9 years agoHelpfull: Yes(0) No(1)
- 9, 3, 6, 21, 9, 12, 33, 15,x
9-3=6
21-9=12
33-15=18(Ans)
- 9 years agoHelpfull: Yes(0) No(0)
- (9-6=3)(21-12=9)
33-48=15..........ans is 48
- 9 years agoHelpfull: Yes(0) No(2)
IBM Other Question
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