What was the day of the week on 17th June, 1998?
Option
A) Monday
B) Tuesday
C) Wednesday
D) Thursday

• Ans: (C)
  
  W.K.T for every 400 days , the no. of odd days is 0
  so upto 1600 year , d no. of odd days ll be "0" only ---->(1)
  
  1601 - 1900 ie for 300 years calculate d no. of odd days
  
  it ll be 15%7 = 1 ----(2)
  
  from 1901 - 1997
  d no. of leap years in 98 yrs ll be 97/4 = 24 yrs nd ordinary yrs 97-24 =73 [v shuld not include 98 bcoz its not yet completed]
  
  so no. of odd days in 97 yrs 24 *2+73*1= 121%7= 2 --->(3)
  
  in 1998 -- calculate the no. of days till june 17th
  31+28+31+30+31+17 [ since 1998 is not a leap year, feb contains 28 days only]
  =168%7= 0 ---->(4)
  
  
  so the total no. of odd days in 1998 yrs is
  
  0 + 1 + 2 + 0 = 3
  
  0 --- sunday
  1 --- monday
  .
  .
  
  so the day is wednesday [ since d total no. of odd days =3]
  
  Ans: (C)
• 10 years agoHelpfull: Yes(11) No(1)
• Wednesday
  D = d+m+yy+q+c
  Where d--->day of month
  m---->month offset
  January 0
  February 3
  March 3
  April 6
  May 1
  June 4
  July 6
  August 2
  September 5
  October 0
  November 3
  December 5
  yy--->Last two digits of the year
  q---->quotient of (yy/4)
  c----->century offset (add 0 for 1900 and 6 for 2000)
  
  D =17+4+98+24+0 = 143
  
  R=Remainder of(D/7)
  = 3
  R Day
  0 Sunday
  1 Monday
  2 Tuesday
  3 Wednesday
  4 Thursday
  5 Friday
  6 Saturday
  
  The day of the week on 17th June, 1998 is wednesday
• 10 years agoHelpfull: Yes(8) No(0)
• It was Wednesday on 17 june 1998.
• 10 years agoHelpfull: Yes(3) No(1)
• please anyone can share trick for this question.
• 10 years agoHelpfull: Yes(1) No(1)