How many values of 'c' results in rational roots which are integer in
x^2-5x+c.
Options
a) 1
b) 3
c) 6
d) Infinite

• equation is
  x^2-5x+c=0
  
  => x = [5 +- √(25-4c)]/2
  
  c=0 => x = 5,0
  c=4 => x = 4,1
  c=6 => x = 2,3
  c=-6 => x = 6, -1
  .......
  
  thus we see that, for c = 0,4,6,-6,... we get rational roots which are integers
  
  no. of values of c = infinite
• 10 years agoHelpfull: Yes(49) No(2)
• take c which could be -c or +c.So there are infinite ways to divide c or -c to get -5.That's why the answer is infinite values of c
• 10 years agoHelpfull: Yes(8) No(0)
• only 1 solution
  x^2-5x+6
  =>x(x-3)-2(x-3)
  =>(x-3)(x-2)
  =>x=3,2
• 10 years agoHelpfull: Yes(0) No(11)
• what is d meaning of rational roots which r integer???????
• 10 years agoHelpfull: Yes(0) No(5)
• x^2-5x+6=0
  
  '6' satisfy the equation.....
  
  hence option (3) is correct
  
• 10 years agoHelpfull: Yes(0) No(4)
• option 3 is correct
  
• 10 years agoHelpfull: Yes(0) No(2)