Q. If u,v,w,x,y and z are non negative integer ,each less than 11,then how many distinct combination(u,v,x,y,z) satisfy v(11^4)+w(11^3)+x(11^2)+y(11)+z(1)=151001

• Only 1 distinct combination is possible.
  It can be solved by finding corresponding number in base 11.
  
  So here V= 10, W=3,X=4,Y=10,Z=4
  
  If 10 is represeted as V, then no in base 11 is
  
  V34V4
• 13 years agoHelpfull: Yes(9) No(5)
• Correct answer is : B
  
  Explanation
  
  11(11^3v+11^w+11x+y) + z = 11*13727 + 4 [hence; z = 4] because I=QN+R : (11*13727+4)
  
  repeating the above procedure;
  
  11(11^2v + 11w +x) + y =11*1247 + 10 [y = 10]
  11(11v + w ) + x = 11*113 + 4 [x = 4]
  11v + w = 11*10 + 3 [v=10 , w=3]
  
• 10 years agoHelpfull: Yes(3) No(1)
• z=151001%11=4
  
  value=151001-4=150997
  
  y(11)=150997%121=110
  
  y=110/11=10
  
  value=150997-11*10=150887
  
  x(11^2)=150887%1331=484
  
  x=484/121=4
  
  value=150887-484=150403
  
  w(11^3)=150403%(11^4)=3993
  
  w=3993/1331=3
  
  value=150403-3993=146410
  
  v(11^4)=146410
  
  v=146410/14641=10
  
  one combination z=4,y=10,x=4,w=3,v=10
• 9 years agoHelpfull: Yes(0) No(0)