One fast typist type some matter in 2hrs and another slow typist type the same matter in 3hrs If both

Ans----> 1 hr 12 min

fast and slow typist's 1 hr work (they are working together) 1/2 + 1/3 = 5/6
so, work will finish in 6/5 hr i.e. 1 hr 12 min
10 years agoHelpfull: Yes(5) No(1)
short cut formulae:
xy/(x+y)

x=2 y=3
3*2/(3+2)=6/5 i.e. 1hr 12min
10 years agoHelpfull: Yes(4) No(1)
work done by
a in 1 hr->1/2
b in 1 hr->1/3
total work done by a & b in 1hr=(1/2+1/3)=5/6
5/6th of work completed in ->1hr
complete work done ->6/5=1.2hrs
10 years agoHelpfull: Yes(2) No(2)
1/2+1/3=5/6
=50mts
10 years agoHelpfull: Yes(1) No(0)
first typist take=2 hrs
second typist take= 3 hrs
both together take = 2*3/5
=6/5
i.e= 1 1/5
10 years agoHelpfull: Yes(0) No(1)
1/2+1/3=5/6
time=6/5
=1.2hrs
10 years agoHelpfull: Yes(0) No(0)
Fast's 1 hr work = 1/2
slow's 1 hr work = 1/3

1/2 + 1/3 = 5/6

they ll finish in 6/5hrs= 1 1/5 ==> 1 hr 12 mins
10 years agoHelpfull: Yes(0) No(0)
Fast's 1 hr work = 1/2
slow's 1 hr work = 1/3

1/2 + 1/3 = 5/6

they ll finish in 6/5hrs= 1 1/5 ==> 1 hr 12 mins
10 years agoHelpfull: Yes(0) No(0)
1/2+1/3=5/6
then 6/5
10 years agoHelpfull: Yes(0) No(0)

One fast typist type some matter in 2hrs and another slow typist type the same matter in 3hrs. If both do
combine in how much time they will take to finish.