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20 people going to one temple. (some time waste data) They want Rs. 20. For men-Rs.3, women-Rs.2, children-50 paisa. How much money spends for men, children and women?
Read Solution (Total 9)
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- we cannot solve for three variables using two equations
- 10 years agoHelpfull: Yes(18) No(1)
- Rs.3,Rs.7,Rs.10
Let number of men be x, women y and children z
x+y+z = 20 ---(1)
men gives 3 rupees each --->total money spend by men = 3x
women gives 2 rupees each--->total money spend by women =2y
children gives 50 paisa each ---> total money spend by children = 0.5z
Total 20 rupees is given by all
3x+2y+0.5z = 20 ---(2)
Solving (1) and (2)
x=1 , y=5 , z = 14
total money spend by men = 3x = Rs3
total money spend by women =2y = 2*5 = Rs10
total money spend by children = 0.5z = 0.5*14 = Rs7 - 10 years agoHelpfull: Yes(17) No(20)
M=1 => 1*3= 3
W=5 => 5*2= 10
C=14 => 14*.5= 7
1+5+14= 20 & 3+10+7=20
- 10 years agoHelpfull: Yes(11) No(1)
- x+y+z=20
3x+2y+0.5z=20
now verify it from option - 10 years agoHelpfull: Yes(3) No(0)
- Ann Theressa , plz explain how did u solve the value of 3 unknowns using 2 equations?????
- 10 years agoHelpfull: Yes(1) No(1)
- @JYOTSHANA
by trail and error method.
the 2 equations are
x+y+z = 20 ---(1)
and
3x+2y+0.5z = 20 ---(2)
multiply eqn (1) by 2
2x+2y+2z = 40 ---(3)
eqn (3) - (2) gives
-x + 3/2*z = 20
3/2 *z = 20 + x
Since x,y and z are positive numbers,from this equation 3/2*Z must be greater than 20.(z > 13)
From equation (1) z is less than or equal to 18.(min value of x and y can be 1)
Also from equation (2) , z must be an even number.
So z can be 14,16 or 18
Lets take z = 14
3/2*z = 20+x
x = 1
x+y+z = 20
so y = 5
Substituting these values in eqn (2)
3x + 2y + 0.5z = 3+10+7 = 20
which satisfies both the equations.
- 10 years agoHelpfull: Yes(1) No(5)
- its a random methodology.
since fr women rs 2 it is even .so rs fr men and child to be odd so tat total 20rs is even.
choose appropriately u vl get answer within 3 possible inputs
- 10 years agoHelpfull: Yes(0) No(0)
- 0.5*14=7 3*3=9 2*3=6 men 3 women 3 children 14 total 20 rs 20
- 7 years agoHelpfull: Yes(0) No(0)
- a) Rs.6-men, Rs.4-children, Rs.10- women
b)Rs.3-men, Rs.7-children, Rs.10- women
c)Rs.3-men, Rs.8-children, Rs.9- women
d)Rs.9-men, Rs.3-children, Rs.8- women
Sol: By using options we calculate it easily.
From option b
Men - 1men*Rs.3= Rs.3
Children - 14children* 50paisa= Rs.7
Women - 5women*Rs.2= Rs.10 - 6 years agoHelpfull: Yes(0) No(0)
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