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log base e (e(e(e..)^(1/2))^(1/2))^(1/2)

Read Solution (Total 1)

7/8
log base e e[e[e^1/2]^1/2]^1/2
1/2[log base e e[e[e^1/2]^1/2]

we know log ab= loga + logb & log base e e= 1

1/2[log base e e + log base e e[e^1/2]^1/2]
1/2[1+ 1/2log base e e[e^1/2]]
1/2[1+1/2[1+ log base e[e^1/2]]]
1/2[1+1/2[1+1/2]
1/2+1/4+1/8
=7/8
13 years agoHelpfull: Yes(3) No(1)

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