IBM
Company
Logical Reasoning
Number Series
What is the next number of the following sequence
21(1/5), 7(2/3), 2, 23(1/5), 8(2/3), 4, 25(1/5), ....
Read Solution (Total 4)
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- 21(1/5),7(2/3),2,23(1/5),8(2/3),4,25(1/5), x, y
[21(1/5),7(2/3),2],[23(1/5),8(2/3),4],[25(1/5),x,y]
21(1/5),7(2/3),2,
23(1/5),8(2/3),4,
25(1/5), x , y
x=9(2/3) y=6 - 10 years agoHelpfull: Yes(33) No(3)
- Group the number sequence as follows:
21(1/5), 7(2/3), 2
23(1/5), 8(2/3), 4
so the next group will be
25(1/5), 9(2/3), 6
so 9(2/3) is the answer
- 10 years agoHelpfull: Yes(12) No(2)
- ans:6
given series can be devided as follows....
21(1/5) , 7(2/3) , 2
next odd number of 21 is 23, next num of 7 is 8,next multilple of 2 is 4
23(1/5) , 8(2/3) , 4
next series will be
25(1/5) , 9(2/3) ,6 - 10 years agoHelpfull: Yes(2) No(0)
- 9(2/3) because every 2/3 fraction is incremented by 1
- 7 years agoHelpfull: Yes(0) No(0)
IBM Other Question
Q. What is the next number of the following sequence
32, 29, 26, 64, 61, 58, 96, 93, 93, ...
What is the next number of the following sequence.
8, 8, 6, 2,.... ?