If 3y + x > 2 and x + 2y <= 3 , What can be said about the value of y?
Option
A. y = -1
B. y >-1
C. y <-1
D. y = 1

• 
  3y + x > 2 -----(1)
  
  x + 2y < = 3
  => x + 2y + y < = 3 + y
  => x + 3y < = 3 + y -----(2)
  from (1)&(2)
  
  2 < 3y + x < 3 + y
  => 2 < 3 + y
  => -1 < y
  => y > -1
  
  B. y > -1
• 10 years agoHelpfull: Yes(35) No(0)
• option b
  
  x+2y = 3
  x =3-2y
  
  putting the value of x into other equation,
  
  3y+3-2y > 2
  y > -1
• 10 years agoHelpfull: Yes(3) No(0)
• 3y+x>2 so x>2-3y (i) ;
  x+2y
• 10 years agoHelpfull: Yes(1) No(0)
• as 3y+x>2 so x>2-3y (i)
  and x+2y
• 10 years agoHelpfull: Yes(0) No(0)
• ans:A
  by solving given 2 eqns we will get y>
• 10 years agoHelpfull: Yes(0) No(0)
• Multiply the second equation with -1 then it will become - x - 2y≥ - 3. Add the equations. You will get y > -1.
  
• 10 years agoHelpfull: Yes(0) No(0)
• 3y+x>2---(1)
  x+2y2
  =>y>-1
• 10 years agoHelpfull: Yes(0) No(0)
• 3y + x > 2 -----(a)
  
  x + 2y < = 3
  => x + 2y + y < = 3 + y
  => x + 3y < = 3 + y ---(b)
  using a and b both
  2 < 3y + x
• 10 years agoHelpfull: Yes(0) No(0)
• it is y=1;
  3(1)+1is>2;(if x=1)
  1+2*(1)
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• as 3y+x>2 OR x+3y-2>0........................1
  next x+2y0 OR Y>-1
• 9 years agoHelpfull: Yes(0) No(0)