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Numerical Ability
Percentage
If the price of an item is decreased by 10% and then increased by 10%, the net effect on the price of the item is
a. A decrease of 99%
b. No change
c. A decrease of 1%
d. An increase of 1%
Read Solution (Total 24)
-
- initially assume 100 rupees
10% discount in 100 gives price of 90 rupees
then 10% raise in 90 is only 9 rupees.
therefore total price =99 rupees.
hence 1% is the loss
- 10 years agoHelpfull: Yes(33) No(1)
- loss of 1% use the formula loss=[x/10]^2
- 10 years agoHelpfull: Yes(10) No(2)
- c) A decrease of 1%
Let x be the price
Decrease by 10%-->
New price = x - x*10/100
=0.9x
Increase in 10%
New price = 0.9x + 0.9*10/100
=0.99x
Net effect =( x - 0.99x)/x *100 = 1% derease - 10 years agoHelpfull: Yes(7) No(1)
- ans:C
let initial price= x
10%decrease===> price=90x/100
10%increase==> new price= (90x/100)+ 10% of 90x/100
= 99x/100
effect on price= new- initial
= 99x/100 - x
=-1/100
-ve sign indicates decrease in cost.... - 10 years agoHelpfull: Yes(2) No(0)
- option c
let initial price = 100
100 ---->(10% decrease) 90 ---->(10% increase) 99
net effect =(100-99)/100 x 100 %
=1% decrease - 10 years agoHelpfull: Yes(2) No(0)
- initially assume 100 rupees
10% discount in 100 gives price of 90 rupees
then 10% raise in 90 is only 9 rupees.
therefore total price =99 rupees.
hence 1% is the loss - 10 years agoHelpfull: Yes(2) No(0)
- x=-10% y=10%
overall change=x+y+x*y/100
=-10+10-10*10/100
=-1 %
A decrease of 1% - 10 years agoHelpfull: Yes(2) No(0)
- -10+10+((-10)*(10)/100)=-1%
- 9 years agoHelpfull: Yes(2) No(0)
- if increase and decrease of item percentage is same then there is a direct formula
p^2/100
put p=10 and we get (100/100)=1% decrease. - 10 years agoHelpfull: Yes(1) No(0)
- 1.1*0.9=0.99 , compare with 1 so 1% decrease.....
- 10 years agoHelpfull: Yes(1) No(0)
- b there is no change
- 10 years agoHelpfull: Yes(0) No(7)
- ans is c,,,,,,,,
- 10 years agoHelpfull: Yes(0) No(0)
- c) a decrease of 1%
suppose the price of the item is x
then decreased by 10 %
net price of the item is 9x/10
then increased by 10%
then the net price of the item will be 9*11x/100=99x/100
that means the price of the item is decreased by 1% - 10 years agoHelpfull: Yes(0) No(0)
- b.nochange
- 10 years agoHelpfull: Yes(0) No(10)
- it can be solve like
-(x)^2/100
where x is the value of increment and decrement
so
-(10)^2/100=-1 - 10 years agoHelpfull: Yes(0) No(0)
- inc%-dec%-dec%*inc%/100
10-10-10*10/100
hence -1% - 10 years agoHelpfull: Yes(0) No(0)
- Answer is C clearly we can easily solve by taking 100 initially
- 10 years agoHelpfull: Yes(0) No(0)
- Option c,
Let price be 100
New price will be 90
On incr
10/100*90=9
Loss of 1% - 10 years agoHelpfull: Yes(0) No(0)
- net effect is decreases by 1% so ans is c
- 9 years agoHelpfull: Yes(0) No(0)
- c decrease by 1%
- 9 years agoHelpfull: Yes(0) No(0)
- .90*1.1=.99 i.e 1 % decrease
- 9 years agoHelpfull: Yes(0) No(0)
- for both increase and decrease=(10/10)*(10/10)=1
=> no change b) - 9 years agoHelpfull: Yes(0) No(0)
- In this type of question when the price is increased and decreased by value same value x. Then there is always a loss of
(x/10)^2 - 9 years agoHelpfull: Yes(0) No(0)
- Ans :option(C)
- 7 years agoHelpfull: Yes(0) No(0)
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