If m is an odd integer and n an even integer, which of the following is definitely odd?

a. (2m+n)(m-n)
b. (m+n2)+(m?n2)
c. m2+mn+n2
d. m +n

• D) m+n
  odd + even = odd
• 10 years agoHelpfull: Yes(22) No(2)
• obviously option D
  PROOF:
  suppose,
  odd int m=2a+1
  even int n=2a
  
  Substitute in option D
  m+n = 2a+1+2a =4a +1
  1 indicates integer in always odd
• 10 years agoHelpfull: Yes(9) No(1)
• d is right because odd and even no sum always equal to odd no..
  so answer is D.m+n
  
• 10 years agoHelpfull: Yes(2) No(0)
• ans:D
  sum of even and odd integers is always odd
• 10 years agoHelpfull: Yes(1) No(0)
• m+n definitely odd
  
• 10 years agoHelpfull: Yes(1) No(1)
• d sum of even and odd is odd
• 10 years agoHelpfull: Yes(0) No(0)
• option d
  let m=7 n=4
  m+n=11 i.e. odd
• 10 years agoHelpfull: Yes(0) No(0)
• b c and d
  
• 10 years agoHelpfull: Yes(0) No(0)
• My Answer is: D
  
  m+n
  for ex: m=1, n=2 1+2=3(odd)
  m=7, n=4 7+4=11(odd)
  m=99,n=2014 99+2014=2113(odd)
  
  (odd number add with even number it always result to an odd number)
• 10 years agoHelpfull: Yes(0) No(0)
• m=7,n=8 then m+n=7+8=15 ,so 15 is the odd integer
  ans-d(m+n)
• 10 years agoHelpfull: Yes(0) No(0)
• b,c,d are odd
• 10 years agoHelpfull: Yes(0) No(0)
• m+n are always odd
• 10 years agoHelpfull: Yes(0) No(0)
• d as odd+even will always be odd
  
• 10 years agoHelpfull: Yes(0) No(0)
• D) m+n is odd
  because the sum of odd and even is always odd
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• d bcz evn + odd = od
• 10 years agoHelpfull: Yes(0) No(0)
• D.m+n because the sum of an even and an odd number is always an odd number.
  Ex: 3 is an odd number and 6 is an even number. Now, 3+6=9, is an odd number.
• 10 years agoHelpfull: Yes(0) No(0)
• addition of one even number and one odd number gives odd number
  e.g:3+4=7
  11+16=27
• 10 years agoHelpfull: Yes(0) No(0)
• subtitute for m and n value ... n check for the odd numb
  if we take m-3 and n=2...for m+n=3+2=5(which is odd)
  hence answer is D
• 10 years agoHelpfull: Yes(0) No(0)
• A and D
  As in option A (2*m+n)->(2*odd=even + even)=even
  now in m-n-> (odd-even =odd)
  
  so even *odd is odd....
  
  In option D -> add +even is odd
• 10 years agoHelpfull: Yes(0) No(0)
• even+odd=odd
  m+n
• 10 years agoHelpfull: Yes(0) No(0)
• lets take m=3 as odd and n=2 as even then a) (2m+n)(m-n) = 8 which is not odd thn check d) m+n=5 which is odd so option d is correct :)
• 10 years agoHelpfull: Yes(0) No(0)
• c and d always gives odd values
• 8 years agoHelpfull: Yes(0) No(0)
• d. sum of even and odd is always odd
• 8 years agoHelpfull: Yes(0) No(0)
• addition of an odd and an even is always odd.
  example:3(odd)+2(even)=5(odd).
• 8 years agoHelpfull: Yes(0) No(0)