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Numerical Ability
Number System
If m is an odd integer and n an even integer, which of the following is definitely odd?
a. (2m+n)(m-n)
b. (m+n2)+(m?n2)
c. m2+mn+n2
d. m +n
Read Solution (Total 24)
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- D) m+n
odd + even = odd - 10 years agoHelpfull: Yes(22) No(2)
- obviously option D
PROOF:
suppose,
odd int m=2a+1
even int n=2a
Substitute in option D
m+n = 2a+1+2a =4a +1
1 indicates integer in always odd - 10 years agoHelpfull: Yes(9) No(1)
- d is right because odd and even no sum always equal to odd no..
so answer is D.m+n
- 10 years agoHelpfull: Yes(2) No(0)
- ans:D
sum of even and odd integers is always odd - 10 years agoHelpfull: Yes(1) No(0)
- m+n definitely odd
- 10 years agoHelpfull: Yes(1) No(1)
- d sum of even and odd is odd
- 10 years agoHelpfull: Yes(0) No(0)
- option d
let m=7 n=4
m+n=11 i.e. odd - 10 years agoHelpfull: Yes(0) No(0)
- b c and d
- 10 years agoHelpfull: Yes(0) No(0)
- My Answer is: D
m+n
for ex: m=1, n=2 1+2=3(odd)
m=7, n=4 7+4=11(odd)
m=99,n=2014 99+2014=2113(odd)
(odd number add with even number it always result to an odd number) - 10 years agoHelpfull: Yes(0) No(0)
- m=7,n=8 then m+n=7+8=15 ,so 15 is the odd integer
ans-d(m+n) - 10 years agoHelpfull: Yes(0) No(0)
- b,c,d are odd
- 10 years agoHelpfull: Yes(0) No(0)
- m+n are always odd
- 10 years agoHelpfull: Yes(0) No(0)
- d as odd+even will always be odd
- 10 years agoHelpfull: Yes(0) No(0)
- D) m+n is odd
because the sum of odd and even is always odd - 10 years agoHelpfull: Yes(0) No(0)
- d bcz evn + odd = od
- 10 years agoHelpfull: Yes(0) No(0)
- D.m+n because the sum of an even and an odd number is always an odd number.
Ex: 3 is an odd number and 6 is an even number. Now, 3+6=9, is an odd number. - 10 years agoHelpfull: Yes(0) No(0)
- addition of one even number and one odd number gives odd number
e.g:3+4=7
11+16=27 - 10 years agoHelpfull: Yes(0) No(0)
- subtitute for m and n value ... n check for the odd numb
if we take m-3 and n=2...for m+n=3+2=5(which is odd)
hence answer is D - 10 years agoHelpfull: Yes(0) No(0)
- A and D
As in option A (2*m+n)->(2*odd=even + even)=even
now in m-n-> (odd-even =odd)
so even *odd is odd....
In option D -> add +even is odd - 10 years agoHelpfull: Yes(0) No(0)
- even+odd=odd
m+n - 10 years agoHelpfull: Yes(0) No(0)
- lets take m=3 as odd and n=2 as even then a) (2m+n)(m-n) = 8 which is not odd thn check d) m+n=5 which is odd so option d is correct :)
- 9 years agoHelpfull: Yes(0) No(0)
- c and d always gives odd values
- 8 years agoHelpfull: Yes(0) No(0)
- d. sum of even and odd is always odd
- 8 years agoHelpfull: Yes(0) No(0)
- addition of an odd and an even is always odd.
example:3(odd)+2(even)=5(odd). - 8 years agoHelpfull: Yes(0) No(0)
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