In a normal 5-day work week, each of 12 employees produces 300 items per day-last week, 1/3 of the employees were absent from work for 2/5 of the days in the week. how many total items were produced last week?
Option
a) 18000
b) 14400
c) 6000
d) 15600
e) 16,200

• 15600 items
  
  1 employee produces 300 items per day
  
  1/3 of the employees were absent for 2/5 days of last week.
  ==> 4 employees were absent for 2 days.
  
  Items produced by them in 3 days
  = 300*3*4
  =3600
  
  Items produced by other employees
  =8*5*300
  =12000
  
  Total items produced = 12000+3600
  =15600
  
• 10 years agoHelpfull: Yes(48) No(5)
• 15600
  total item produce by 12 employee in 5 days.
  = 12*5*300
  =18000 items
  item produce by those absent empoyee
  =4*2*300
  =2400 items
  so originally total item produce
  =18000-2400
  = 15600 items Ans.
• 9 years agoHelpfull: Yes(40) No(1)
• (Day) (Man) (Iteam)
  5 12 18000
  2 8 ?
  18000*4/12*2/5=2400
  So,(18000-2400)=15600
• 9 years agoHelpfull: Yes(4) No(1)
• Total no. of employee = 12
  1/3 of employee ==> 12 * 1/3 = 4
  So 4 employees were absent for 2/5 of the days
  
  So for 2/5 days , 12 - 4 employees only worked
  
  for 12 employees, 300 items produced
  for (12-4) , x
  
  x= 8/12 * 300 = 200
  So 200 items produced on d day of employees absent
  
  4 employees absent only for 2/5 days (ie) 2 days... Remaining 3 days , all d employees worked together...
  
  So total items produced last week = 3*300 + 2*200 = 1300
  
  Ans : 1300 items
• 10 years agoHelpfull: Yes(3) No(15)
• 1300
  
  employees----items
  12 ---- 300
  1 -----x
  
  x = 300/12 = 25
  1 employee produces 25 items per day.
  
  1/3 of the employees were absent for 2/5 days of last week.
  ==> 4 employees were absent for 2 days.
  
  Items produced by them in 3 days
  = 25*3*4
  =300
  
  Items produced by other employees
  =8*5*25
  =1000
  
  Total items produced = 1000+300
  =1300
  
  
• 10 years agoHelpfull: Yes(2) No(8)
• Option is a.18000 b.14400 C.6000 D.15600 E.16,200
• 10 years agoHelpfull: Yes(1) No(1)
• 12 employees ,each produce 300
  means total 12*300=3600 per day
  for 5 days = 3600*5= 18000
  
  1/3 absent for2/5 days ==> 4/12 absent for2/5 days
  
  4 absent for 2 days
  4*300 =1200 for 1 day . for 2 days 2400
  
  since they dont work , remove that 2400 from total (if allhave worked =18000)
  
  18000-2400= 15600
• 9 years agoHelpfull: Yes(1) No(1)
• According to question total namdays work is
  5*12=60
  produces 300 items
  The wrok going through
  5*(2/5)*12+(1-2/3)*5*(12*1/3)
  =24+12
  =3*12
  60 manpower produce 300
  36 '' '' (300/60)*36=180
  Ans is 180
• 10 years agoHelpfull: Yes(0) No(2)
• @ANN THERESSA....
  
  
  1 employee doesnt produce 300 items per day... 12 employee produces 300 item per day....
  
  
  look at the solution of saraswathi..
• 9 years agoHelpfull: Yes(0) No(3)
• ans 16200
  
  Since 1/3rd of employees were absent from work for 2/5 days. Therefore,
  For 2/5 i.e. 2 days ---> 8 employees work for 2 days and produce 300 items per day so -- > 8*2*300=5400
  
  For remaining 3 days -- > 12 employees work for 3 days and produce 300 items per days so --> 12*3*300=10800
  
  i.e. Total items produced = 5400+10800=16200 is the ans.
• 9 years agoHelpfull: Yes(0) No(3)