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Numerical Ability
Percentage
A Company finds that 62% of applicants pass its hiring test. if 10212 applicants took the test last year and 23% more applicants took the test this year?
Read Solution (Total 3)
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No of applicants took the test = 10212 + 23% of 10212
=12560.76
=12560
62% pass every year
===>38% fail every year
No. of applicants failed this year = 38/100*12560
= 4773- 10 years agoHelpfull: Yes(5) No(0)
- ans is 4773
- 10 years agoHelpfull: Yes(1) No(0)
- total no. of student=10212
23% is more means 10212+23%=10212*23/100=2349(round off value bz of no. of student)
therefore total no. of student = 10212+2349 = 12561
now 62% passed
i.e 12591*62/100 = 7788(passed)
fail = total no of student - passed
12561 - 7788 = 4773
- 10 years agoHelpfull: Yes(0) No(0)
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