given three points P,Q,R WITH P(5,3) and R lies on x-axis.if equation of RQ is x-2y=2 and PQ is parallel to x-axis then the centroid of triangle PQR lies on the line

• (5,2)
  
  P (5,3)
  
  equation of RQ is
  x - 2y = 2
  
  Given R lies on x-axis. So at point R y co-ordinate is 0
  x - 2*0 = 2
  x = 2
  
  R (2,0)
  
  PQ is parallel to x axis
  ===> y co-ordinate of Q and P are same. ie 3
  
  From equation of RQ
  x - 2*3 = 2
  x = 8
  
  Q (8,3)
  
  Centroid = ((x1+x2+x3)/3 , (y1+y2+y3)/3 )
  =((5+2+8)/3 , (3+0+3)/3)
  =(5,2)
  
• 10 years agoHelpfull: Yes(0) No(0)
• the centroid can lie on any line bcuz infinite lines (ex. y=2 or x=5 and so on)can cross through a point in this case the centroid is at(5,2).
• 10 years agoHelpfull: Yes(0) No(0)
• the centroid is at(5,2)
• 10 years agoHelpfull: Yes(0) No(0)