AIEEE
Exam
Numerical Ability
Number System
If a,b,c are non zero real numbers and az2+bz+c+i=0 has purely imaginary roots, then a=
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- underroot(b^2-(4a(c+i))).... so for the root to be imaginary the equation inside the root should be negative soooo...
4a(c+i)>(b^2) therefore a>(b^2)/(c+i). - 10 years agoHelpfull: Yes(1) No(0)
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