The least number which is to be added to the greater number of 4 digits so that sum may be divisible by 345.

• Greater number of 4 digits = 9999
  For any number to be divisible by 345, it should be divisible by 5, 3, 23...
  
  9999 is divisible by 3, but not divisible by 5 nd 23...
  When we divide 9999 by 23, it leaves a remainder 17... So if we add 6 [(ie) 17+6=23] to 9999, the result ll be exactly divisible by 5 nd 23... [(ie)9999+6=1005...]
  
  So the least no. to be added is 6 nd the number obtained is 10005
  
  Ans : 6
• 10 years agoHelpfull: Yes(27) No(0)
• greatest 4 digit number is 9999(may be greatest is the correct placement of the question..)
  if the qestion is with greatest 4 didgit number the answer is 6 as10005 is divisable by 345 and it is 6 lower than 9999....
• 10 years agoHelpfull: Yes(0) No(0)
• better see options and follow check and tick method..........
• 10 years agoHelpfull: Yes(0) No(0)