M4maths
Maths Puzzle
Numerical Ability
Number System
if
2+3=8,
3+7=27,
4+5=32,
5+8=60,
6+7=72,
then
7+8=??
Solve it?
Read Solution (Total 23)
-
2*(2-1) + 2*3 => 2+6 = 8
3*(3-1) + 3*7 => 6+21 = 27
4*(4-1) + 4*5 => 12+20 = 32
5*(5-1) + 5*8 => 20+40 = 60
6*(6-1) + 6*7 => 30+42 = 72
7*(7-1) + 7*8 => 42+56 = 98
Ans : 98- 10 years agoHelpfull: Yes(18) No(0)
- 98
2+3--> 2*(3+1) = 2*4 = 8
3+7--> 3*(7+2) = 3*9 = 27
4+5--> 4*(5+3) = 4*8 = 32
5+8--> 5*(8+4) = 5*12 = 60
6+7--> 6*(7+5) = 6*12 = 72
7+8--> 7*(8+6) = 7*14 = 98
- 10 years agoHelpfull: Yes(5) No(0)
- 7+8=7*(8+6) = 7*14 = 98
- 10 years agoHelpfull: Yes(1) No(0)
- (2*1)+(2*3)=8
(3*2)+(3*7)=27
(4*3)+(4*5)=32
(5*4)+(5*8)=60
(6*5)+(6*7)=72
(7*6)+(7*8)=98 - 10 years agoHelpfull: Yes(1) No(0)
- Ans-98 diagonal addition then * beside no. (2+7)*3
- 10 years agoHelpfull: Yes(1) No(0)
- 7*(8+6)=98
- 10 years agoHelpfull: Yes(1) No(0)
- 98 will be the answer
- 10 years agoHelpfull: Yes(0) No(0)
- take 2+3
2(1)+3(2)=2+6=8
3(2)+7(3)=6+21=27
lke that
7(6)+8(7)=42+56=98
is the ans - 10 years agoHelpfull: Yes(0) No(0)
- 2+3 = 2*(3+1)=8
3+7 = 3*(7+2)=27
4+5 = 4*(5+3)=32
i.e. first number is multiplied by sum of second number and (first number-1)
hence, 6+7 = 6*(7+5)= 72
similarly 7+8 = 7*(8+6) = 7*14 = 98ANS - 10 years agoHelpfull: Yes(0) No(0)
- 2*1+3*2=8
2*1+3*2=8
3*2+7*3=27
4*3+5*4=32
5*4+8*5=60
6*5+7*6=72
7*6+8*7=98
ans=98 - 10 years agoHelpfull: Yes(0) No(0)
- 2*3=6+2*1=8
3*7+3*2=27
4*5+4*3=32
.
.
7*8+7*6=98 - 10 years agoHelpfull: Yes(0) No(0)
- 2*(3+1)=8
3*(7+2)=27,
4*(5+3)=32,
5*(8+4)=60,
6*(7+5)=72,
then
7*(8+6)=98. - 10 years agoHelpfull: Yes(0) No(0)
- (2*3)+(2-1)=8
Solution:-multiplt both the digits and u will find the product suppose X...then subtract the first digit by 1 and then multiply it by the original first digit....and the product obtained is suppose Y....and finally add both X+Y=answer
Therefore the ans. Is 98
(7*8)+[(7-1)7]=98 - 10 years agoHelpfull: Yes(0) No(0)
- 3*2+2*1=8; 7*3+3*2=27 ;5*4+4*3=32..........
8*7+7*6=98 - 10 years agoHelpfull: Yes(0) No(0)
- 2*1+3*2=8
3*2+7*3=27
.
.
.
7*6+8*7=98
so ans is 98 - 10 years agoHelpfull: Yes(0) No(0)
- 98
2+3=8,
3+7=27 =>3*(7+2)=27,
4+5=32 =>4*(5+3)=32,
5+8=60 =>5*(8+4)=60,
6+7=72 =>6*(7+5)=72,
7+8=98 =>7*(8+6)=98 - 10 years agoHelpfull: Yes(0) No(0)
- ANSWER is 98;
2*3+2=8; 3*7+6=27; 4*5+12=32; 5*8+20=60; 6*7+30=72;
so the series of no. which is added is 2 ,6,12,20,30
6-2=4; 12-6=6; 20-12=8; 30-20=10; x-30=12, x=42;
so 7*8+42=98; - 10 years agoHelpfull: Yes(0) No(0)
- ans is 98
2*1+3*2=8
3*2+7*3=27
4*3+5*4=32
5*4+8*5=60
6*5+7*6=72
7*6+8*7=98 - 10 years agoHelpfull: Yes(0) No(0)
- 7*8+7*6=98
- 10 years agoHelpfull: Yes(0) No(0)
- ans=98 bcz 2*2=4 9*3=27 so 14*7=98
- 10 years agoHelpfull: Yes(0) No(0)
- 2+3=8 ,(sum of 2 and 3 is 5) 5*2 - 2=8
3+7=27 , (sum of 3 and 7 is 10) 10*3 - 3=27
4+5=32 , 9*4 - 4=32
5+8=60 , 13*5 - 5=60
6+7=72 , 13*6 - 6=72
7+8= 98 , 15*7-7=98 - 8 years agoHelpfull: Yes(0) No(0)
- 2+3-1=4*2=8
3+7-1=9*3=27
4+5-1=8*4=32
5+8-1=12*5=60
6+7-1=12*6=72
7+8-1=14*7=98 - 7 years agoHelpfull: Yes(0) No(0)
- (2+3)*1+3=5+3=8
(3+7)*2+7=20+7=27
(4+5)*3+5=27+5=32
(5+8)*4+8=52+8=60
(6+7)*5+7=65+7=72
(7+8)*6+8=90+8=98 - 6 years agoHelpfull: Yes(0) No(0)
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