The height of a conical tent is 14 m and its floor
area is 346.5 m2. The length of 1.1 m wide canvas
required to built the tent is

• pi*r^2 = 346.5
  r^2 =346.5*7/22=441/4
  r =21/2
  then length L=sqrt(r^2 + h^2)=sqrt(441/4+(14)^2)=sqrt(1225/4)=35/2
  So, area of canvas needed =
  pi*r*L=(22/7)*(21/2)*(35/2) m^2
  =(33*35)/2 m^2
  Length of canvas =(33*35)/(2*1.1)m = 525 m.
• 10 years agoHelpfull: Yes(4) No(0)
• 360 degree=2*pi*r
  72degree=((2*pi*r)*2)/10
  so required ratio=(4*pi*r)/(20*pi*r)
  so ans is 1:5
  Read more at http://www.m4maths.com/today_puzzle.php#HE2Ie0lOlQz3LgOB.99
• 10 years agoHelpfull: Yes(0) No(1)