A person climbs up to a pole of 88 m high. In every min he climbs 12 m but slips down 8 m...how much time will he take to reach d top????

• 4+44+444+4444+-- in this series ,there are 9 terms ,if we add them all,which number will be in the term of the sum ?
  
  A(5),B(9),C(2),D(6) WHAT IS THE ANS
• 9 years agoHelpfull: Yes(7) No(1)
• 20 minutes
  
  person climbs 12 m in a minute & slips down 8 m
  so,he goes up 12-8 = 4 m up in a minute
  
  thus, in 19 minutes, he will be 19*4= 76 m up
  on 20 th minute he will be at top of the pole i.e at 76+12 = 88 m & willn't slip down.
• 10 years agoHelpfull: Yes(3) No(0)
• in every min person climbs up 12m and slips 8m . hence net displacement becomes 4m.
  in 19 minutes person would climb (19*4)=76m
  in 20th minute person would climb 12m up.. and it will be on top.
  hence in 20th minute. person will reach on pole.
• 10 years agoHelpfull: Yes(2) No(0)
• it should be 39min
  2min=12-8=4meter
  ?min=88-12=76
  (2*76)/4=38 min
  at 38 min it should be on 76 meter
  at 39 min 76+12=88meter
• 7 years agoHelpfull: Yes(0) No(1)
• 88/4
  so 22 min to reach the top
• 7 years agoHelpfull: Yes(0) No(1)