How many combinations are possible if 3 one rupee coin, 4 fifty paise coin and 2 twenty five paise coin are available. It is compulsory to select any one of the coin

• Total possible combinations = (3+1)*(4+1)*(2+1)=60
  But It is compulsory to select any one of the coin.
  so 0 one rupee coin, 0 fifty paise coin and 0 twenty five paise coin selection is not allowed.
  so desired combinations = 60-1=59
  
  
  
• 10 years agoHelpfull: Yes(5) No(1)
• (3c1*4c0*2c0)+(3c0*4c1*2c0)+(3c0*4c0*2c1) = 9................
• 10 years agoHelpfull: Yes(1) No(2)
• we can choose any coin in two way whether we are choosing it or not...i.e.for selecting any coin we have two option
  so total combination of selection of zero or more coins=
  2+2+2+2+2+2+2+2+2=18
  but we have to selct at least one
  so ans is 18-1=17
  
• 10 years agoHelpfull: Yes(1) No(0)
• we must take atleast one coin from each
  they don't give overally,,how many coins we take
  so,we consider all possible combinations
  solution is:
  [(3c1+3c2+3c3)*4c1*2c1]+[3c1*(4c1+4c2+4c3+4c4)*2c1]+[3c1*4c1*(2c1+2c2)]+
  [(3c1+3c2+3c3)*4c2*2c1]+[3c2*(4c1+4c2+4c3+4c4)*2c1]+[3c2*4c1*(2c1+2c2)]+
  [(3c1+3c2+3c3)*4c3*2c1]+[3c3*(4c1+4c2+4c3+4c4)*2c1]+[3c3*4c1*(2c1+2c2)]+
  ...........................................................
  like that we will take all possible situations
  but, it is very difficult to calculate this..
  so,any one please tell me the small logic to this problem
• 10 years agoHelpfull: Yes(0) No(1)
• total coins=9
  so combination =9!=362880
• 7 years agoHelpfull: Yes(0) No(0)