If the hypotenuse of right angel triangle is 13 m and its base is 12m, then find its height.

• (hyp)^2 = (base)^2+(height)^2
  13^2 = 12^2+(height)^2
  169 = 144+(height)^2
  (height)^2 = 25
  height = 5
  
  Ans : 5
  
• 10 years agoHelpfull: Yes(5) No(0)
• let height be p metres
  Given ,
  hypotenuse,h=13m
  base,b=12m
  according to pythagoras theorem,h^2=p^2+b^2;
  13^2=p^2+12^2;
  on solving we get p=5 m
  
• 10 years agoHelpfull: Yes(1) No(0)
• 13*13=12*12+a*a A2+ B2 = C2
  169-144=25
  a=5
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• (hyp)^2-(base)^2=(height)^2
  (13)^2-(12)^2=169-144
  25=(5)^2
  height=5
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• Ans. Is 5
  So simple...
  Pythagoras rule
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• (hyp)^2 = base^2+perp^2
  13^2 = 12^2+p^2
  25=p^2
  p=5
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• Ans is 5
  a^2=b^2+c^2
  13^2=12^2+c^2
  169-144=c^2
  c^2=25
  c=5m
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• 5
  sqrt(13^2-12^2)
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• ans: 5 ,
  according to pythagoras theorem
  
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• Hypoteneous ^2 = base ^2 + height ^2
  
  So height ^ 2 = 13^2 - 12 ^2
  =25
  height = 5m
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• hyp^2=base^2+height^2
  13*13=121*12+h^2
  
  therfore H^2=169-144=>52
  H=5
• 10 years agoHelpfull: Yes(0) No(0)