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Numerical Ability
Probability
You have Rs.2 with u.You have to play a game in which if u win u will get 1 Re. and if lost you will lose 1 Re.You can lose up to 3 times. But if u get 5 Rs, you are left out of the game. In how many ways is this possible?
Read Solution (Total 16)
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- case 1: I win every game
WWW =1
he has three rupees
case 2: I lose 1 game
so the number of combination will be 4
LWWWW, WLWWW, WWLWW, WWWLW
case 3: I lose 2 games
combinations will be 15
LLWWWWW, WLLWWWW, WWLLWWW, WWWLLWW, WWWWLLW, LWLWWWW, LWWLWWW, LWWWLWW,
LWWWWLW, WLWLWWW, WLWWLWW, WLWWWLW, WWLWLWW, WWLWWLW, WWWLWL
case 3:I lose 3 games
so combination will be
LLLWWWWWW, WLLLWWWWW, WWLLLWWWW, WWWLLLWWW, WWWWLLLWW, WWWWWLLLW
LLWLWWWWW, LLWWLWWWW, LLWWWLWWW, LLWWWWLWW, LLWWWWWLW
WLLWLWWWW, WLLWWLWWW, WLLWWWLWW, WLLWWWWLW, WWLLWLWWW, WWLLWWLWW
WWLLWWWLW, WWWLLWLWW, WWWLLWWLW, WWWWLLWLW, LWLLWWWWW, LWWLLWWWW
LWWWLLWWW, LWWWWLLWW, LWWWWWLLW, WLWLLWWWW, WLWWLLWWW, WLWWWLLWW
WLWWWWLLW, WWLWLLWWW, WWLWWLLWW, WWLWWWLLW, WWWLWLLWW, WWWWLWLLW
LWLWLWWWW, LWLWWLWWW, LWLWWWLWW, LWLWWWWLW, WLWLWLWWW, WLWLWWLWW
WLWLWWWLW, WWLWLWLWW, WWLWLWWLW, WWWLWLWLW
SO total of 40 combination is possible if I loose 3 games
so total number of ways in which i will win rs 5 and leave the game is
1+4+15+46=66
- 10 years agoHelpfull: Yes(20) No(18)
- already Rs.2
2+(3 win) ----> 1 way
Maximum 3 loss
2+(6 win)(- 3 loss) : 9!/6!*3!
2+(5 win)(-2 loss) : 7!/5!*2!
2+(4 win)(-1 loss) : 5!/4!*1!
1+(9!/6!*3!)+(7!/5!*2!)+(5!/4!*1!)= 111 - 10 years agoHelpfull: Yes(9) No(5)
- @ SHABIH ABBAS in case 2 and 3 after 3 wins www the person will be out of the game so many combinations (in case 2 and 3) which you have given will not come.
- 10 years agoHelpfull: Yes(5) No(1)
- ans is 66 ways.
- 10 years agoHelpfull: Yes(1) No(33)
- ans is 76
for combination WWW-1
for combination WLWWW->4!/3!=4
for combination WLLWWWW->6!/(4!*2!)=15
for combination WLLLWWWWW->7!/(3!*5!)=56
TOTAL=56+15+4+1=76 - 9 years agoHelpfull: Yes(1) No(1)
- Now the logic of the Question is in this that he can be out of the game as soon as he gets 5 Rs and a maximum of 3 loses are allowed
for 0 lose
we have number of ways until he gets point 5 and is out of the game as 3!/3!=1
for 1 lose
number of ways are =4!/3!=4
for 2 lose it is
number of ways are =6!/4!=15
for 3 lose it is
number of ways are =46
so total ways are 1+46+15+4=66
- 9 years agoHelpfull: Yes(1) No(0)
- plzz explain
- 10 years agoHelpfull: Yes(0) No(2)
- can anyone xplain plz???
- 10 years agoHelpfull: Yes(0) No(1)
- can anyone expalin it .??
- 10 years agoHelpfull: Yes(0) No(3)
- plz explain this
- 10 years agoHelpfull: Yes(0) No(2)
- can any one explain it
- 10 years agoHelpfull: Yes(0) No(1)
- plz explain
- 10 years agoHelpfull: Yes(0) No(0)
- case 1: lwlwl
case 2: wwlll
case 3: wllwl
case 4: llwwl
case 5: lwwll
so in 5 ways - 10 years agoHelpfull: Yes(0) No(4)
- please explain the sum?
- 10 years agoHelpfull: Yes(0) No(0)
- Now the logic of the Question is in this that he can be out of the game as soon as he gets 5 Rs and a maximum of 3 loses are allowed
for 0 lose
we have number of ways until he gets point 5 and is out of the game as 3!/3!=1
for 1 lose
number of ways are =4!/3!=4
for 2 lose it is
number of ways are =6!/4!=15
for 3 lose it is
number of ways are =46
so total ways are 1+46+15+4=66
- 9 years agoHelpfull: Yes(0) No(0)
- 91ways...
1+6p1+7p2+(7p2*1)=91 ways - 9 years agoHelpfull: Yes(0) No(0)
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