what will be the o/p of the program
void main()
{
int const * p=5;
printf("%d",++(*p));
}

• Error ...
  
  We cannot modify a constant variable... Here *p is a const variable which always holds 5 only... We cannot modify that...
• 10 years agoHelpfull: Yes(25) No(2)
• 6
  it's not giving a compiler error because firstly we find value of p at pointer location after this we increment like this
  *p=5++
  6
• 10 years agoHelpfull: Yes(1) No(2)
• error
  we can't convert 'int' to 'const int *'
• 10 years agoHelpfull: Yes(1) No(0)
• int const *p means that p is a pointer variable that is pointing to a constant variable.so while changing the variable value by deferring gives an error!
• 10 years agoHelpfull: Yes(1) No(0)
• it will be error
• 10 years agoHelpfull: Yes(1) No(0)
• error because p is constant cannot be modified
• 10 years agoHelpfull: Yes(0) No(0)
• 5,p is declared as constant so its value will not change.
• 10 years agoHelpfull: Yes(0) No(0)
• plz give me right answer admin
• 10 years agoHelpfull: Yes(0) No(0)
• comile error
  
• 8 years agoHelpfull: Yes(0) No(0)
• #include
  
  int main()
  {
  int N1=7,N2=24,i,sum=0;
  for(i>0;i7)
  {
  sum=sum+i;
  }
  
  }
  printf("%d",sum);
  }
• 5 years agoHelpfull: Yes(0) No(0)