what will be the o/p of the program
main()
{
char s[ ]="man";
int i;
for(i=0;s[ i ];i++)
printf("n%c%c%c%c",s[i ],*(s+i),*(i+s),i[s]);
}

• Output :
  mmmm
  aaaa
  nnnn
  
  Assume the base address of s=1000 ... so address of s[0]=1000, s[1]= 1001, s[2]=1002
  
  s[0]=m, s[1]=a, s[2]=n
  s[i] => s[0] = m
  *(s+i) => *(1000+ 0) = *(s) => m
  +(i+s) => *(0+1000) = *(S) => m
  i[s] is equal to s[i]... both are equal... So for 1st iteration, all ll print "m", nd 2nd iteration it ll print "a" nd 3rd it ll print "n"...
  
  Hence mmmm, nnnn, aaaa
  
• 10 years agoHelpfull: Yes(33) No(7)
• nmmmm,naaaa,nnnnn
• 10 years agoHelpfull: Yes(10) No(0)
• o/p
  nmmmmnaaaannnnn
  s[i],*(s+i),*(i+s),i[s] these all are same.......
• 10 years agoHelpfull: Yes(1) No(0)
• nmmmmnaaaannnnn
• 10 years agoHelpfull: Yes(1) No(0)
• it will be
  nmmmmnaaaannnnn
  because for i=0 it will be = nmmmm (n is coming from "n.....")
  for i=1 it will be = naaaa(again n is coming from "n.....")
  for i=2 it will be= nnnnn (again n is coming from "n....")
  so o/p = nmmmmnaaaannnnn
• 10 years agoHelpfull: Yes(1) No(0)
• output: nmmmmnaaaaannnnn
  
• 10 years agoHelpfull: Yes(1) No(0)
• nmmmmnaaaannnnn
• 10 years agoHelpfull: Yes(1) No(0)
• sorry mmmm,aaaa,nnnn
• 10 years agoHelpfull: Yes(0) No(3)
• mmmm
  aaaa
  nnnn
• 10 years agoHelpfull: Yes(0) No(0)
• output: mmmaaannn
• 10 years agoHelpfull: Yes(0) No(0)
• output -
  nmmmmnaaaannnnn
• 10 years agoHelpfull: Yes(0) No(0)
• mmmm
  aaaa
  nnnn
  loop will iterate and print character one by one...condition is s[i]!=0
• 10 years agoHelpfull: Yes(0) No(0)
• print operation may be error
  
• 9 years agoHelpfull: Yes(0) No(0)
• nmmmmnaaaannnnn
• 9 years agoHelpfull: Yes(0) No(0)
• it will give error message because array defined of character types excepts value with ' '
  
• 9 years agoHelpfull: Yes(0) No(2)
• it will give error message because array defined of character types excepts value with ' '
  
• 9 years agoHelpfull: Yes(0) No(1)
• it will give error message because array defined of character types excepts value with ' '
  
• 9 years agoHelpfull: Yes(0) No(1)
• it will give error message because array defined of character types excepts value with ' '
  
• 9 years agoHelpfull: Yes(0) No(1)
• it will give error message because array defined of character types excepts value with ' '
  
• 9 years agoHelpfull: Yes(0) No(1)
• it will give error message because array defined of character types excepts value with ' '
  
• 9 years agoHelpfull: Yes(0) No(1)
• it will give error message because array defined of character types excepts value with ' '
  
• 9 years agoHelpfull: Yes(0) No(1)