Sum of 36 odd numbers is?

• sum of 1st n odd no.s = 1+3+5+7+... = n^2
  
  so, Sum of 1st 36 odd numbers = 36^2 = 1296
• 10 years agoHelpfull: Yes(25) No(2)
• Here n=36, and A.P = 1+3+5+7+....
  so last term = a+(n-1)d= 1+(36-1)2=71
  sum = 36/2(1+71)= 36*36 = 1296
• 10 years agoHelpfull: Yes(15) No(0)
• sum of a series..Ap..n/2(2a+(n-1)/d)...1276
• 10 years agoHelpfull: Yes(3) No(0)
• 36^2=36*36=1296
  
• 10 years agoHelpfull: Yes(1) No(0)
• even..coz sum of odd no of odd nos is odd and if they are in even numbers then even
• 10 years agoHelpfull: Yes(1) No(1)
• 1+3+5+7......
  so it is A.P.
  with a=1
  n=32, d=2
  sum of A.P is n/2(2a+(n-1)d)=1296
• 10 years agoHelpfull: Yes(1) No(0)
• n=36,
  A.P = 1+3+5+7+....
  last term = a+(n-1)d= 1+(36-1)2=71
  sum = 36/2(1+71)= 36*36 = 1296..........
• 10 years agoHelpfull: Yes(1) No(0)
• oops...1296....
• 10 years agoHelpfull: Yes(0) No(0)
• sum of a series..Ap..n/2(2a+(n-1)/d)...1276
• 10 years agoHelpfull: Yes(0) No(0)
• ans will be 1296
• 10 years agoHelpfull: Yes(0) No(0)