IIT-JEE
Exam
Numerical Ability
Percentage
A sum of 4000 is lent over 5 years at the interst of 15 per annum. Find the interesy
Read Solution (Total 3)
-
- p = 4000
t = 5 yrs
r = 15%
SI = p*r*t/100
=> 4000*15*5/100 => 3000
Ans : Rs. 3000 - 10 years agoHelpfull: Yes(4) No(0)
- Ans: 3000
p=4000;
r=15%;
t=5;
s.i=p*r*t/100 ; - 10 years agoHelpfull: Yes(0) No(0)
- P= Rs. 4000
N= Rs. 4 yrs
R= 15% per annum
I= ?
therefore, I = P*N*R/100
=4000*4*15/100 = Rs. 2400 - 10 years agoHelpfull: Yes(0) No(0)
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