Book Maths Puzzle Algebra

Find two consecutive odd integers such that the square of the first, added to 3 times the second, is 24.

Read Solution (Total 2)

Let x, (x+2) be the 2 odd integers

x^2 + 3(x+2) = 24
x^2 + 3x + 6 = 24
x^2 + 3x - 18 = 0
(x+6) ( x-3) = 0
x=-6 or x=3
Given both are odd numbers
So x=3, (x+2)= 5

So the 2 consecutive odd no's are 3,5
10 years agoHelpfull: Yes(3) No(0)

let no be x,(x+2)
a/q
x^2+3x+6=24
x^2+3x-18=0
=> x=-6 x=3
odd number is 3
3,5 are integers
10 years agoHelpfull: Yes(0) No(0)

Book Other Question

The sum of the squares of two consecutive integers is 41. Find the integers Find two consecutive even integers such that the square of the second, decreased by twice the first, is 52.