Find two consecutive even integers such that the square of the second, decreased by twice the first, is 52.

• Let x, (x+2) be the 2 even integers
  
  (x+2)^2 - 2x = 52
  x^2 + 4 + 4x - 2x - 52 = 0
  x^2 + 2x - 48 = 0
  (x+8) (x-6) = 0
  x=-8 or x=6
  
  if x=6, x+2=8
  If x=-8, x+2=-6
  
  So the 2 integers are 6,8 or -8,-6
  
• 10 years agoHelpfull: Yes(4) No(0)
• let integers be x & x+2,
  a/q,
  (x+2)^2 - 2x =52
  => x^2+2x-48=0
  =>x= -8 & x=6
  thus no are -8,-6 and 6,8
• 10 years agoHelpfull: Yes(0) No(0)