There Is An Escalator And 2 Persons Move Down It. A Takes 50 Steps And B Takes 75 Steps While The
Escalator Is Moving Down. Given That The Time Taken By A To Take 1 Step Is Equal To Time Taken By B To
Take 3 Steps. Find The No. Of Steps In The Escalator While It Is Stationary.

• If S is no of steps In The Escalator While It Is Stationary.
  A Takes 50 Steps And B Takes 75 Steps While The
  Escalator Is Moving Down.
  Given That The Time Taken By A To Take 1 Step Is Equal To Time Taken By B To
  Take 3 Steps.
  
  If A takes time 't' secs to take 50 steps, B takes (t/50)*(75/3) = t/2 secs
  
  Then speed of escalator remains same in 2 cases.
  so (S-50)/t = (S-75)/2t
  so S -50= 2s-150
  s=100
• 13 years agoHelpfull: Yes(17) No(1)
• If A takes 1 step in one second, then B takes 3 steps in one second. If A takes t1 seconds to take 50 steps, then B takes 150 steps in t1 seconds.
  
  For B, to take 150 steps he requires t1 seconds,
  
  then to take 75 steps he requires t1/2 seconds.
  
  So now, s1=50, t1 = t1 & s2=75, t2=t1/2
  
  ans= (s1*t2 ~ s2*t1) / (t1 ~ t2) which gives 100.
  
  so 100 steps is the answer
• 13 years agoHelpfull: Yes(5) No(4)