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Numerical Ability
Ratio and Proportion
There are some people in party , 1/3rd left the party . Then 2/5th of the remaining left the party , then 2/3rd of the remaining left the party . At last 6 were remaning . How many people were in total ?
Read Solution (Total 5)
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- 45
If x persons were there in total , then
x*(1-1/3)* (1-2/5) *(1-2/3) = 6
x*2/3 * 3/5 *1/3 = 6
x= 6*5*3/2 = 45 - 13 years agoHelpfull: Yes(10) No(1)
- 45
Let total persons in party are =X
then remaining = X*2/3*3/5*1/3=6
It gives X=45 - 13 years agoHelpfull: Yes(5) No(1)
- ans=45
total people 3*5*3=45 - 13 years agoHelpfull: Yes(0) No(1)
- let there is x people
after1/3 left then there is 2x/3
then after 2x/5
then 2x/15=6
so x=45 - 13 years agoHelpfull: Yes(0) No(1)
- (2/3*3/5*1/3)x=6
->x=45 - 13 years agoHelpfull: Yes(0) No(2)
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